縮短代碼到1行

Question

好的，所以我遇到一個問題，要求在main方法的1行代碼中重寫此代碼：

public static void main(String[] args)
String s;
    boolean b;
    JOptionPane jop;

    jop = new JOptionPane();

    s = jop.showInputDialog("Enter your email address");
    b = s.matches(".*@.*\\..*");
    if (b)
    {
        System.out.println("Address Appears Valid");
    }
    else
    {
        System.out.println("Address is Invalid");
    }
}

這是我到目前為止所做的

public static void main( String[] args )
{

   String s = JOptionPane.showInputDialog("Enter your email address");

   System.out.println(s.matches(".*@.*\\..*") ? "Address Appears Valid" : "Address is Invalid" );
}

如何進一步縮短此代碼？ 謝謝

Answer 1

做這個：

String s = JOptionPane.showInputDialog("Enter your email address");

   System.out.println(s.matches(".*@.*\\..*") ? "Address Appears Valid" : "Address is Invalid" );

變成這個：

System.out.println(JOptionPane.showInputDialog("Enter your email address").matches(".*@.*\\..*") ? "Address Appears Valid" : "Address is Invalid" );

畢竟，如果只打算在下一行中使用它，為什么還要存儲它呢？

Answer 2

不要在println中創建s，pur joption

Answer 3

public static void main( String[] args )
{
   System.out.println(JOptionPane.showInputDialog("Enter your email address").matches(".*@.*\\..*") ? "Address Appears Valid" : "Address is Invalid" ));
}

需要注意的重要一點是，輸入對話框將返回一個僅使用一次的字符串。 因此，無需存儲它，而僅在返回時使用它。

Answer 4

只需從您的源中刪除所有CR / LF字符即可：)