[英]Getting 'Syntax Error' on jade view
我正在嘗試一個簡單的聊天應用程序使用簡單的玉視圖引擎與快遞。 當我運行我的應用程序時,我在下面的視圖代碼上遇到語法錯誤。 但它就這么簡單。
extends layout
block scripts
script(type='text/javascript', src='/socket.io/socket.io.js')
script(type='text/javascript')
var socket = io.connect('http://localhost:8080');
socket.on('chat', function(data) {
document.getElementById('chat').innerHTML = '<p><b>' + data.title + '</b>: ' + data.contents + '</p>';
});
var submitChat = function(form) {
socket.emit('chat', {text: form.chat.value});
return false;
};
block content
div#chat
form(onsubmit='return submitChat(this);')
input#chat(name='chat', type='text')
input(type='submit', value='Send Chat')
我收到了這個錯誤:
SyntaxError: views/chat.jade:9
7| document.getElementById('chat').innerHTML =
8| '<p><b>' + data.title + '</b>: ' + data.contents + '</p>'; >
9| });
10| var submitChat = function(form) {
11| socket.emit('chat', {text: form.chat.value});
12| return false;
Unexpected token ; at Function (<anonymous>) at assertExpression
好像你錯過了一個簡單的點 ,請參閱Jade Reference 。
例如:
script(type='text/javascript')
var socket = io.connect('http://localhost:8080');
會給
<script type="text/javascript">
<var>socket = io.connect('http://localhost:8080');</var>
</script>
並且您得到了Unexpected token
錯誤。
script(type='text/javascript').
var socket = io.connect('http://localhost:8080');
為了向您展示示例中的差異,上面的代碼將給出:
<script type="text/javascript" src="/socket.io/socket.io.js"></script>
<script type="text/javascript">
var socket = io.connect('http://localhost:8080');
</script>
所以你的代碼應該是這樣的:
extends layout
block scripts
script(type='text/javascript', src='/socket.io/socket.io.js')
script(type='text/javascript').
var socket = io.connect('http://localhost:8080');
socket.on('chat', function(data) {
document.getElementById('chat').innerHTML = '<p><b>' + data.title + '</b>: ' + data.contents + '</p>';
});
var submitChat = function(form) {
socket.emit('chat', {text: form.chat.value});
return false;
};
block content
div#chat
form(onsubmit='return submitChat(this);')
input#chat(name='chat', type='text')
input(type='submit', value='Send Chat')
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.