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[英]Is there an easier way to filter columns in a Laravel Resource Collection?
[英]Good way to filter multiple DB columns in Laravel
我想再次過濾多個數據庫列的結果,但是我現在的方式似乎一點都不是Laravel的:)
有沒有更好的辦法? 我不想在末尾堆積所有這些sql
語句。
$data = Input::except('_token');
if (isset($data['passenger_name']))
{
$passenger_name = $data['passenger_name'];
} else {
$passenger_name = '*';
}
if (isset($data['passenger_lastname']))
{
$passenger_lastname = $data['passenger_lastname'];
} else {
$passenger_lastname = '*';
}
// Run query
$q = Reservation::where('passenger_firstname', 'LIKE', '%'. $passenger_name .'%')
->where('passenger_lastname', 'LIKE', '%' . $passenger_lastname .'%')
->get();
return View::make('dashboard')->with('reservations', $q);
這些只是我要針對其運行查詢的許多條件中的兩個
您可以嘗試以下方法:
$query = Reservation::query();
if(Input::has('passenger_name')) {
$query->where('passenger_name', Input::get('passenger_name'));
}
if(Input::has('passenger_lastname')) {
$query->where('passenger_lastname', Input::get('passenger_lastname'));
}
$reservations = $query->get();
return View::make('dashboard')->with('reservations', $reservations);
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