如何在Ruby Join查詢中編寫此SQL查詢（Ruby on Rails）

Question

SELECT rs.id as rs_id,
sum(rs.amount_per_month) as rs_am1,
sum(rs.amount_per_month_per_sqft) as rs_am2,
rs.from_date,rs.to_date,cc.charge_type as cc 
FROM   lease_rent_rolls as lrr 
INNER JOIN leases as l ON  lrr.lease_id = l.id 
INNER JOIN rents as r ON l.id = r.lease_id 
INNER JOIN rent_schedules as rs ON r.id = rs.rent_id 
INNER JOIN charge_codes as cc ON rs.charge_code_id = cc.id 
WHERE lrr.id = 449443 
AND   DATE(NOW()) BETWEEN rs.from_date AND rs.to_date 
GROUP BY cc.charge_type

我在使用find_by_sql模型中使用此SQL查詢，但是我應該在沒有SQL幫助的情況下在Ruby Joins中獲得相同的結果。

Answer 1

如果您將提供關聯，那么提供解決方案將更有用。

現在，我正在考慮：

LeaseRentRoll有一個或多個租約。

租賃有很多租金。

租金有很多租金時間表。

和RentSchedule有許多charge_code。

如果LeaseRentRoll有一項租約：

LeaseRentRoll.where(:id => 449443).first.lease.joins(:rents => [:rent_schedules => charge_codes]).select("rent_schedules.id as rs_id, sum(rent_schedules.amount_per_month) as rs_am1, sum(rent_schedules.amount_per_month_per_sqft) as rs_am2,

rent_schedules.from_date，rent_schedules.to_date，charge_codes.charge_type as cc“）

如果LeaseRentRoll有許多租約：

LeaseRentRoll.where(:id => 449443).first.leases.joins(:rents => [:rent_schedules => charge_codes]).select("rent_schedules.id as rs_id, sum(rent_schedules.amount_per_month) as rs_am1, sum(rent_schedules.amount_per_month_per_sqft) as rs_am2, rent_schedules.from_date,rent_schedules.to_date,charge_codes.charge_type as cc")

請看附件圖片。 這將有助於對上述查詢有更多的了解。

Answer 2

RentSchedule.joins([{:rent => {:lease => :lease_rent_rolls}}, :charge_code]).where("lease_rent_rolls.id = #{lease_rr.id} 
and rent_schedules.from_date < '#{Date.today.strftime("%Y-%m-%d %H:%M:%s")}' 
and rent_schedules.to_date > '#{Date.today.strftime("%Y-%m-%d %H:%M%s")}'").group("charge_codes.charge_type")

得到了該查詢的結果。謝謝大家！

Answer 3

像這樣：

@goods =Good.joins(:user).where("name like ?", "%#{@searched_good}%").where("category_id = ?", params[:category]).where("postal_code == ?", @searched_good_postal_code)

其中：-category_id和name屬於Good數組-postal_code屬於User數組