[英]How to insert into mysql table using ajax?
我想使用ajax將數據插入表中,因此數據將插入而無需重新加載頁面。
此代碼很好地將數據插入表中,但代碼也重新加載頁面。
但我想要插入而不重新加載頁面。
我怎樣才能做到這一點 ?
<?php
include('connection.php');
if(isset($_POST['cmt'])){
$comment = addslashes($_POST['cmt']);
$alertid = $_POST['alert_id'];
mysql_query("INSERT INTO `comments` (`id`, `alert_id`, `comment`, `username`) VALUES (NULL, '".$alertid."', '".$comment."', 'tomas')");
}
?>
<script>
function submitform(){
var comment = $("#comment").val();
var alertid = $("#alertid").val();
$.ajax({
type: "POST",
//url: "ana.php",
data:{cmt:comment,alert_id:alertid}
}).done(function( result ) {
$("#msg").html( result );
});
}
</script>
<form method = "POST" onsubmit = "submitform()">
<textarea onFocus = "myFunction(1)" onBlur = "myFunction(0)" style="margin: 0px 0px 8.99305534362793px; width: 570px; height: 50px;" rows = "6" cols = "40" id = "comment"></textarea><br />
<input type = "text" placeholder="Enter Maximium 100 Words" id = "alertid" value = "10">
<input type = "submit" name = "submit" value = "Comment">
</form>
試試這個添加它來形成onsubmit =“return submitform();”
function submitform(){
var comment = $("#comment").val();
var alertid = $("#alertid").val();
$.ajax({
type: "POST",
//url: "ana.php",
data:{cmt:comment,alert_id:alertid}
}).done(function( result ) {
$("#msg").html( result );
});
return false;
}
你必須創建一個php文件,在你的表中插入發布的數據並用ajax調用它:
$.ajax({
url: "/file.php",
type: "POST",
cache: false,
dataType: "json",
data: postValue,
success: function(results) {
bootbox.alert(results.message, function() {
bootbox.setIcons(null);
window.location.reload();
});
},
error: function(results) {
bootbox.alert(results.message, function() {
bootbox.setIcons(null);
});
}
});
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