[英]Hit Api and get Response using http post and curl
大家好,我是一名初級php開發人員,我正在將Java代碼轉換為php ..在Java api上命中並正確獲得響應,現在我試圖在php中使用curl http post命中這是我在我的軟件公司plz中的任務幫我
我要向您展示我的Java代碼正確運行,然后我的php代碼無法正常工作並且不解析該API的參數,因此請您指導我
這是我的Java代碼,它工作正常,我想從php做同樣的工作
import java.io.*;
import java.util.jar.JarException;
import org.apache.http.HttpResponse;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.entity.StringEntity;
import org.apache.http.impl.client.DefaultHttpClient;
import org.json.*;
class MyCode{
public static void main(String[] args) throws JarException, JSONException
{
testCustomerApiIsExposed();
}
public static void testCustomerApiIsExposed() throws JarException, JSONException {
try {
@SuppressWarnings("deprecation")
HttpClient c = new DefaultHttpClient();
HttpPost p = new
HttpPost("http://link");
String payload = "{id:\"" + 1 + "\"," + "method:\"" + "customerApi.getApiToken" + "\", params:[\"teabonezenminddemo1partner@gmail.com\", \"demo1234!\", \"\", \"\", \"\", \"\", \"\", false, \"\", \"\"" + "]}";
String mimeType="";
/*There is something here. What constructor are we really calling here? */
// p.setEntity(new StringEntity( payload,ContentType.create("application/json")));
p.setEntity(new StringEntity(payload));
HttpResponse r = c.execute(p);
BufferedReader reader = new BufferedReader(new InputStreamReader(r.getEntity().getContent(), "UTF-8"));
StringBuilder builder = new StringBuilder();
for (String line = null; (line = reader.readLine()) != null;) {
builder.append(line).append("\n");
}
JSONTokener tokener = new JSONTokener("[" + builder.toString() + "]");
JSONArray finalResult = new JSONArray(tokener);
JSONObject o = finalResult.getJSONObject(0);
//Getting names of the JSON object here
System.out.println(o.names());
String apiToken = (String) o.get("result");
System.out.println(apiToken);
}
catch(IOException e) {
System.out.println(e);
}
}
}
現在我在php上對此進行編碼,但是沒有得到響應檢查它並指導我我使用curl http post和getApiToken方法幫助我解決這個問題,我非常緊張。
這是我的PHP代碼
<?php
$data = array(params);
$ch = curl_init('http://link');
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($ch, CURLOPT_POSTFIELDS, http_build_query($data));
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
$result = curl_exec($ch);
echo $result;
?>
您正在從Java代碼發布JSON。 因此也可以在PHP上使用json(確保格式正確):
$payload = "{params}";
卷曲選項將是
// as you are posting JSON, so tell server that you are sending json
curl_setopt($ch, CURLOPT_HTTPHEADER, array("Content-Type: application/json"));
// Let server know that you are doing HTTP POST request
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, $payload);
使用這些,我得到了示例響應:
{"id":"1","result":"results"}
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