Ruby on Rails保存到數據庫

Question

嗨，我是Ruby on Rails的初學者。這是我的疑問。 我的控制器中有此方法

def save_profile
    p "======================================"
    p params
    p "======================================"
    p params[:company][:job_locations_attributes]
    p "company_params------------------------"
    p company_params
    p "--------------------------------------"
    company_profile
    @location = JobLocation.new(:city_id => params[:city_id])
    @location.save
    if @company.update_attributes(company_params)
      redirect_to company_dashboard_path(@company.id)
    else
      render 'company_profile'
    end
  end

在終端我得到的輸出像

"======================================"
{"utf8"=>"✓", "authenticity_token"=>"kbId4JgeaM+mGlmZC1U4gFCUYN7LHmuqWq8Es3rxa+k=", "company"=>{"name"=>"Besole", "address"=>"<p>Besole, Besole, Besole, Besole</p>", "employee_count"=>"> 200", "company_type"=>"Business", "foundation_year"=>"2020", "mission"=>"Besolification", "website"=>"https://www.besole.com", "facebook_page_url"=>"https://www.facebook.com/besole", "twitter_page_url"=>"https://www.twitter.com/besole", "description"=>"Besole besole Besole Besole Besole Besole besole", "delete_logo"=>"", "logo_crop_x"=>"", "logo_crop_y"=>"", "logo_crop_h"=>"", "logo_crop_w"=>"", "jobs_attributes"=>{"33"=>{"id"=>"33", "company_id"=>"11", "title"=>"Besoler", "description"=>"<p>besoler besoler besoler</p>", "job_type_id"=>"1", "experience"=>"1 - 3 Years", "job_category_id"=>"2", "skill_ids"=>["", "6", "5", "7", "9", "11", "12", "16", "15"], "_destroy"=>"false"}}, "job_locations_attributes"=>{"33"=>{"job_locations"=>"2"}}}, "city_id"=>"40035", "portfolios_id"=>"321", "commit"=>"Submit", "controller"=>"companies", "action"=>"save_profile", "id"=>"11"}
"======================================"
{"33"=>{"job_locations"=>"2"}}
"company_params------------------------"
{"name"=>"Besole", "logo_crop_h"=>"", "logo_crop_w"=>"", "logo_crop_x"=>"", "logo_crop_y"=>"", "delete_logo"=>"", "address"=>"<p>Besole, Besole, Besole, Besole</p>", "employee_count"=>"> 200", "company_type"=>"Business", "mission"=>"Besolification", "website"=>"https://www.besole.com", "description"=>"Besole besole Besole Besole Besole Besole besole", "foundation_year"=>"2020", "facebook_page_url"=>"https://www.facebook.com/besole", "twitter_page_url"=>"https://www.twitter.com/besole", "jobs_attributes"=>{"33"=>{"id"=>"33", "company_id"=>"11", "title"=>"Besoler", "description"=>"<p>besoler besoler besoler</p>", "job_type_id"=>"1", "experience"=>"1 - 3 Years", "job_category_id"=>"2", "skill_ids"=>["", "6", "5", "7", "9", "11", "12", "16", "15"], "_destroy"=>"false"}}}
"--------------------------------------"

我想獲取33和Job Locations。我想將這兩個變量保存在table Location內的job_id和state_id列下，其中job_id為33而state_id為2

Answer 1

您可以使用它。

job_id = params[:company][:job_locations_attributes].keys[0] 

state_id = params[:company][:job_locations_attributes][job_id]['job_locations']

Answer 2

如果您想簡短一點

job_id, state_id = params[:company][:job_locations_attributes].first

Location.create(:job_id => job_id, state_id => state_id.values[0])

Answer 3

您可以這樣獲得哈希值，

params[:company][:job_locations_attributes].keys.first => "33" 
params[:company][:job_locations_attributes].values.first["job_locations"] => "2"

您可以使用這些值來創建這樣的位置，

Location.create(:job_id => params[:company][:job_locations_attributes].keys.first, :state_id => params[:company][:job_locations_attributes].values.first["job_locations"])

建議從視圖中以單獨的參數發送job_id和state_id，名稱為job_id和state_id ，以便我們可以將job_id和state_id分別作為params[:job_id]和params[:state_id]