帶有正文的Http請求

Question

我需要使用HTTP正文authparams = {“ login”：“ login”，“ password”：“ pasword”}創建POST請求url為http://url.com/api/auth/ ，如何創建它？ 我嘗試

 HttpClient httpClient = new DefaultHttpClient();
        // Creating HTTP Post
        HttpPost httpPost = new HttpPost("http://url.com/api/auth/");
        // Building post parameters, key and value pair
        List<NameValuePair> nameValuePair = new ArrayList<NameValuePair>(2);
        nameValuePair.add(new BasicNameValuePair("login", "A@asd.ru"));
        nameValuePair.add(new BasicNameValuePair("password", "123"));
        // Url Encoding the POST parameters
        try {
            httpPost.setEntity(new UrlEncodedFormEntity(nameValuePair));
        } catch (UnsupportedEncodingException e) {
            // writing error to Log
            e.printStackTrace();
        }
        // Making HTTP Request
        try {
            HttpResponse response = httpClient.execute(httpPost);
            // writing response to log
            Log.d("myLogs:", response.toString());
            HttpEntity entity = response.getEntity();
            Log.d("myLogs:",EntityUtils.toString(entity) );
        } catch (ClientProtocolException e) {
            // writing exception to log
            e.printStackTrace();
        } catch (IOException e) {
            // writing exception to log
            e.printStackTrace();

        }

但我得到一個不好的結果

Answer 1

您需要將帖子數據轉換為Json格式（可以使用Google庫gson或使用org.json）。

然后將您的json字符串添加到發布數據nameValuePair.add(new BasicNameValuePair("login", "A@asd.ru"))

Answer 2

我認為您誤解了您發布的那段代碼。 這只是向服務器發送 POST請求，但當前不處理來自服務器的響應。 為此，您可以使用如下代碼：

InputStream ips;
ips = response.getEntity().getContent();
final BufferedReader buf = new BufferedReader(new InputStreamReader(ips, "UTF-8"));

StringBuilder sb = new StringBuilder();
String s;
while (true) {
  s = buf.readLine();
  if ((s == null) || (s.length() == 0))
    break;
  sb.append(s);
}

buf.close();
ips.close();
Log.i("Response", "My response is: " + sb.toString());