Windows上的pthread和多核

Question

我的問題與pthread庫以及利用多核系統有關。 在適當的參數下和較小的數據量下，系統似乎有所改進，最大的改進是在65000左右。數據表明，當您增加線程數時，它開始減少所需的時間，但此后不久就增加了。 當線程數= 1,2,4時，它可能會緩慢增加，有時是8，但是到16時，時間又開始減少。 在大數據量中，沒有任何改善，並且所有時間都保持相當接近。 如果有人可以告訴我是否有某些事情迫使我的線程按順序執行操作，或者其他問題會令人敬畏。

繼承數據

1395525080 0 num thread: 1 data size: 1024 0 1395525080
1395525080 0 num thread: 2 data size: 1024 0 1395525080
1395525080 0 num thread: 4 data size: 1024 0 1395525080
1395525080 15 num thread: 8 data size: 1024 0 1395525080
1395525080 47 num thread: 16 data size: 1024 0 1395525080
1395525080 31 num thread: 32 data size: 1024 0 1395525080
1395525080 16 num thread: 1 data size: 4096 0 1395525080
1395525080 0 num thread: 2 data size: 4096 0 1395525080
1395525080 0 num thread: 4 data size: 4096 0 1395525080
1395525080 15 num thread: 8 data size: 4096 0 1395525080
1395525080 78 num thread: 16 data size: 4096 0 1395525080
1395525080 31 num thread: 32 data size: 4096 0 1395525080
1395525080 140 num thread: 1 data size: 65536 0 1395525080
1395525081 156 num thread: 2 data size: 65536 0 1395525081
1395525081 109 num thread: 4 data size: 65536 0 1395525081
1395525081 94 num thread: 8 data size: 65536 0 1395525081
1395525081 93 num thread: 16 data size: 65536 0 1395525081
1395525081 187 num thread: 32 data size: 65536 0 1395525082
1395525082 171 num thread: 1 data size: 75536 0 1395525082
1395525082 172 num thread: 2 data size: 75536 0 1395525082
1395525082 141 num thread: 4 data size: 75536 0 1395525083
1395525083 109 num thread: 8 data size: 75536 0 1395525083
1395525083 140 num thread: 16 data size: 75536 0 1395525083
1395525083 234 num thread: 32 data size: 75536 0 1395525084
1395525084 203 num thread: 1 data size: 85536 0 1395525084
1395525084 203 num thread: 2 data size: 85536 0 1395525084
1395525084 172 num thread: 4 data size: 85536 0 1395525085
1395525085 202 num thread: 8 data size: 85536 0 1395525085
1395525085 125 num thread: 16 data size: 85536 0 1395525085
1395525085 187 num thread: 32 data size: 85536 0 1395525086
1395525086 125 num thread: 1 data size: 55536 0 1395525086
1395525086 109 num thread: 2 data size: 55536 0 1395525086
1395525086 141 num thread: 4 data size: 55536 0 1395525086
1395525086 78 num thread: 8 data size: 55536 0 1395525086
1395525087 140 num thread: 16 data size: 55536 0 1395525087
1395525087 156 num thread: 32 data size: 55536 0 1395525087
1395525120 153271 num thread: 1 data size: 70000000 153 1395525274
1395525398 152630 num thread: 2 data size: 70000000 152 1395525551
1395525675 154846 num thread: 4 data size: 70000000 154 1395525830
1395525956 153988 num thread: 8 data size: 70000000 153 1395526110
1395526236 153956 num thread: 16 data size: 70000000 153 1395526390
1395526515 157935 num thread: 32 data size: 70000000 157 1395526673

這是代碼，它執行傳統的存儲桶排序，我還有另外兩個具有相似數據的相似存儲桶，也執行存儲桶排序，順序代碼生成幾乎完全相同的值。

struct bucket
{
    std::vector<int> data;

} ;


void *sort_bucket(void *unsorted_bucket);
int _tmain(int argc, _TCHAR* argv[])
{
    int array_N[] = {1024, 4096, 65536,75536,85536,55536, 70000000, 16777216};
    int array_number_of_threads[] = {1, 2, 4, 8, 16, 32};
    std::vector<int> N;
    std::vector<int> number_of_threads;
    number_of_threads.assign(array_number_of_threads, array_number_of_threads+6);
    N.assign(array_N, array_N+7);

    for(int size_index = 0; size_index < N.size(); size_index++)
    {
        for(int thread_index = 0; thread_index < number_of_threads.size(); thread_index++)
        {
            std::vector<int> unsorted_data;
            std::vector<int> sorted_data;
            std::vector<std::thread> thread_array;
            std::vector<bucket> buckets;

            std::vector<pthread_t> thread;

            while(buckets.size() < number_of_threads[thread_index]){ // checks against the number of threads and creates the number of buckets
                bucket new_bucket;
                pthread_t new_thread;
                buckets.push_back(new_bucket);
                thread.push_back(new_thread);
            }

            for(int index = 0; index < N[size_index]; index++) // gathers the data
            {
                unsorted_data.push_back(rand() % N[size_index]);
            }

            clock_t t = 0;
            t = clock();
            time_t start = 0;
            time_t end = 0;

            time(&start);
            std::cout << start << " ";

            int difference = N[size_index]/number_of_threads[thread_index];
            int placeholder = 0;
            for(int index = 0; index < N[size_index]; index++) {//calculates which bucket the data belong in and places the data in that bucket
                //std::cout << unsorted_data[index] << " " << difference << " ";
                placeholder = unsorted_data[index]/difference;
                //std::cout << placeholder << std::endl;
                buckets[placeholder].data.push_back(unsorted_data[index]);
            }
            for(int index = 0; index < number_of_threads[thread_index]; index++){ // sends the data to the threads
                //thread_array.push_back(std::thread(sort_bucket ,buckets[index]));
                pthread_create(&thread[index],
                               NULL,
                               sort_bucket ,
                               (void*) &buckets[index].data);
            }
            // bring the data back to the root process
            for(int index = 0; index < number_of_threads[thread_index]; index++)        {
                void *data;
                struct bucket *ret_bucket;
                pthread_join(thread[index],(void**) &data);
                ret_bucket = (struct bucket *) data;
                sorted_data.insert(sorted_data.end(), ret_bucket->data.begin(), ret_bucket->data.end());
                //sorted_data.assign(ret_bucket->data.begin(), ret_bucket->data.end());
            }
            /*
             for(int index = 0; index < sorted_data.size(); index++)
             {
             std::cout << sorted_data[index] << " ";
             }
             */

            t = clock() - t;
            std::cout << t << " ";
            t = t/CLOCKS_PER_SEC;
            std::cout << "num thread: " << number_of_threads[thread_index] << " ";
            std::cout << "data size: " << N[size_index] << " ";
            std::cout << t << " ";
            time(&end);
            std::cout << end << std::endl;



            sort(unsorted_data.begin(), unsorted_data.end());

            for(int index = 0; index < unsorted_data.size(); index++)
            {
                if(unsorted_data[index] != sorted_data[index])
                {
                    std::cout << "data sorting failed" << std::endl;
                }
            }
        }
    }
    int placeholder;
    std::cin >> placeholder;
    return 0;
}

void *sort_bucket(void *unsorted_bucket)
{  
    bucket *temp_sorted_bucket = (struct bucket *) unsorted_bucket;  
    std::sort(temp_sorted_bucket->data.begin(), temp_sorted_bucket->data.end()); 

    /*for(int index = 0; index < temp_sorted_bucket->data.size(); index++)
     {
     std::cout << temp_sorted_bucket->data.at(index) << " ";
     }*/
    pthread_exit(temp_sorted_bucket);
    return 0; 
}

Answer 1

請記住，您的線程受CPU上物理內核數量的限制。 達到極限后，它必須使用資源在同一核心上的線程之間切換，這需要時間。 例如，一個i3處理器具有2個帶有超線程的物理內核，這些超線程在CPU上提供4個虛擬內核，因此，超過4個線程的任何操作通常都不會帶來任何好處。