解析數據org.json.JSONException時出錯：輸入的字符0的結尾

Question

我正在嘗試解析來自此url的 JSON數據。

但是我收到這些錯誤：

03-27 16：48：21.019：E / Buffer錯誤（23717）：轉換結果java.lang.NullPointerException時出錯

03-27 16：48：21.059：E / JSON解析器（23717）：解析數據org.json.JSON時出錯：字符0的輸入結束

當我調試代碼時； getJsonFromUrl()方法返回null jobject 。 這是我使用的JSONParser類 。 是什么導致錯誤？

public class JSONParser {

    static InputStream iStream = null;
    static JSONArray jarray = null;
    static JSONObject jObj= null;
    static String json = "";

    public JSONParser() {
    }



    public JSONObject getJSONFromUrl(String url) {

        // Making HTTP request
        DefaultHttpClient httpClient = new DefaultHttpClient();
        HttpPost httpPost = new HttpPost(url);



        try {
            HttpResponse httpResponse = httpClient.execute(httpPost);
            HttpEntity httpEntity = httpResponse.getEntity();
            InputStream is = httpEntity.getContent();
            BufferedReader reader = new BufferedReader(new InputStreamReader(is, "iso-8859-1"), 8);
            StringBuilder sb = new StringBuilder();
            String line = null;
            while ((line = reader.readLine()) != null) {
                sb.append(line + "\n");
            }
            iStream.close();
            json = sb.toString();
        } catch (Exception e) {
            Log.e("Buffer Error", "Error converting result " + e.toString());
        }

        // try parsing the string to a JSON object
        try {
            if (json != null) {
                jObj = new JSONObject(json);
            } else {
                jObj = null;
            }
        } catch (JSONException e) {
            Log.e("JSON Parser", "Error parsing data " + e.toString());
        }

        // return JSON String
        return jObj;

    }
}

我正在使用這些行從另一個類中對此方法進行調用。 （URL參數在頂部定義）

  JSONParser jParser = new JSONParser();
  final JSONObject jobject = jParser.getJSONFromUrl(url);

Answer 1

您嘗試使用HTTP POST方法而不是適當的GET方法（ W3schools.com GET vs.POST ）獲取JSON內容，請修改源代碼以簡化和修復HTTP請求

DefaultHttpClient httpClient = new DefaultHttpClient();
HttpGet get = new HttpGet(url);

try {
    HttpResponse httpResponse = httpClient.execute(get);
    String json = EntityUtils.toString(httpResponse.getEntity());
    System.out.println(json);
    ....
    ....

} catch (Exception e) {
    ....
}