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[英]Python Paramiko - wait on more output from passed command before exiting
[英]What to do from stopping the program from exiting in Python before if command
我使用以下代碼構建一個從用戶獲取輸入的簡單Python程序。
Name = raw_input('Enter your name: ')
Age = raw_input('Enter you age:')
Qualifications = raw_input('Enter you Qualification(s):')
A = raw_input()
print "Hello" +'.'+ "Your Name is " + Name + ". " + "Your Age is " + Age + ". " + "Your Qualification(s) is/are:" + Qualifications + "."
print "If the above data is correct, type yes. If not, type no. Typing no will restart he program and make you write the form again." + A
if A in ['y', 'Y', 'yes', 'Yes', 'YES']:
print 'Thanks for your submission'
if A in ['No' , 'no' , 'NO' ,'n' , 'N']:
reload()
程序在if命令之前完成。
除了['y', 'Y', 'yes', 'Yes', 'YES']
或['No' , 'no' , 'NO' ,'n' , 'N']
,程序將完成並且不執行其各自if
-clauses中的任何語句。
reload()
函數不會按預期執行。 它用於重新加載模塊,應該在解釋器中使用。 它還需要先前導入的module
作為它的參數,調用它不會引發TypeError
。
所以為了再次問問題,你需要一個循環。 例如:
while True:
name = raw_input('Enter your name: ')
age = raw_input('Enter your age: ')
qualifications = raw_input('Enter your Qualification(s): ')
print "Hello. Your name is {}. Your age is {}. Your qualifications are: {}".format(name, age, qualifications)
quit = raw_input("Is the above data correct [yY]? ").lower() # notice the lower()
if quit in ("y", "yes"):
break
else:
# If the input was anything but y, yes or any variation of those.
# for example no, foo, bar, asdf..
print "Rewrite the form below"
如果你現在輸入任何比別的y, Y
或任何變化yes
,該方案將再次提出的問題。
在打印“您的名字是......”之后移動您的A raw_input
行。 像這樣:
我還讓腳本繼續要求重新啟動,直到輸入有效。
Name = raw_input('Enter your name: ')
Age = raw_input('Enter you age:')
Qualifications = raw_input('Enter you Qualification(s):')
print "Hello" +'.'+ "Your Name is " + Name + ". " + "Your Age is " + Age + ". " + "Your Qualification(s) is/are:" + Qualifications + "."
print "If the above data is correct, type yes. If not, type no. Typing no will restart he program and make you write the form again."
yes = ['y', 'Y', 'yes', 'Yes', 'YES']
no = ['No' , 'no' , 'NO' ,'n' , 'N']
A = ''
while A not in (yes+no): # keep asking until the answer is a valid yes/no
A = raw_input("Again?: ")
if A in yes:
print 'Thanks for your submission'
if A in no:
reload()
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