desugaring arrow語法后如何獲得haskell代碼？

Question

我目前試圖解決我的問題HXT：輸入是否可以改變箭頭語法？ 因此，想要在ghc編譯器去掉Arrow語法之后看到haskell代碼。 我怎樣才能做到這一點？

我已經嘗試了-ddump-ds但是有了這個標志我得到了一個可怕的長代碼，因為所有類型都被解析了。 有沒有辦法看到代碼只用箭頭語法desugaring？

Answer 1

原始箭頭項目提供了一個名為arrowp的解析器， 可在Hackage上使用 ，並將箭頭語法轉換為Haskell98：

cabal install arrowp
arrowp --help
arrowp source.hs > desugared.hs

例

來源已從您的其他問題中獲取 。

source.hs

{-# LANGUAGE Arrows #-}
import Text.XML.HXT.Core

data Person = Person { forname :: String, surname :: String } deriving (Show)

parseXml :: IOSArrow XmlTree Person
parseXml = proc x -> do
    forname <- x >- this /> this /> hasName "fn" /> getText
    surname <- x >- this /> this /> hasName "sn" /> getText
    returnA -< Person forname surname

main :: IO ()
main = do
    person <- runX (readString [withValidate no]
                               "<p><fn>John</fn><sn>Smith</sn></p>"
                    >>> parseXml)
    putStrLn $ show person
    return ()

arrowp source.hs

{-# LINE 2 "source.hs" #-}
module Main (main) where
{-# LINE 2 "source.hs" #-}
import Text.XML.HXT.Core

{-# LINE 4 "source.hs" #-}
data Person = Person{forname :: String, surname :: String}
            deriving Show

{-# LINE 6 "source.hs" #-}
parseXml :: IOSArrow XmlTree Person
{-# LINE 7 "source.hs" #-}
parseXml
  = (arr (\ x -> (x, x)) >>>
       (first (this /> this /> hasName "fn" /> getText) >>>
          arr (\ (forname, x) -> (x, forname)))
         >>>
         (first (this /> this /> hasName "sn" /> getText) >>>
            arr (\ (surname, forname) -> Person forname surname)))

{-# LINE 12 "source.hs" #-}
main :: IO ()
{-# LINE 13 "source.hs" #-}
main
  = do person <- runX
                   (readString [withValidate no] "<p><fn>John</fn><sn>Smith</sn></p>"
                      >>> parseXml)
       putStrLn $ show person
       return ()