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[英]UnicodeEncodeError: 'ascii' codec can't encode character u'\xe9'
[英]UnicodeEncodeError: 'ascii' codec can't encode character '\xe9' - -when using urlib.request python3
我正在編寫一個腳本,該腳本轉到鏈接列表並解析信息。
它適用於大多數站點,但它在某些站點上令人窒息,“UnicodeEncodeError:'ascii' 編解碼器無法在位置 13 中編碼字符 '\\xe9':序號不在范圍內(128)”
它在 client.py 上停止,它是 python3 上 urlib 的一部分
確切的鏈接是: http ://finance.yahoo.com/news/cafés-growth-faster-than-fast-food-peers-144512056.html
這里有很多類似的帖子,但似乎沒有一個答案對我有用。
我的代碼是:
from urllib import request
def __request(link,debug=0):
try:
html = request.urlopen(link, timeout=35).read() #made this long as I was getting lots of timeouts
unicode_html = html.decode('utf-8','ignore')
# NOTE the except HTTPError must come first, otherwise except URLError will also catch an HTTPError.
except HTTPError as e:
if debug:
print('The server couldn\'t fulfill the request for ' + link)
print('Error code: ', e.code)
return ''
except URLError as e:
if isinstance(e.reason, socket.timeout):
print('timeout')
return ''
else:
return unicode_html
鏈接 = ' http://finance.yahoo.com/news /cafés-growth-faster-than-fast-food-peers-144512056.html' 頁面 = __request(link)
回溯是:
Traceback (most recent call last):
File "<string>", line 250, in run_nodebug
File "C:\reader\get_news.py", line 276, in <module>
main()
File "C:\reader\get_news.py", line 255, in main
body = get_article_body(item['link'],debug=0)
File "C:\reader\get_news.py", line 155, in get_article_body
page = __request('na',url)
File "C:\reader\get_news.py", line 50, in __request
html = request.urlopen(link, timeout=35).read()
File "C:\Python33\Lib\urllib\request.py", line 156, in urlopen
return opener.open(url, data, timeout)
File "C:\Python33\Lib\urllib\request.py", line 469, in open
response = self._open(req, data)
File "C:\Python33\Lib\urllib\request.py", line 487, in _open
'_open', req)
File "C:\Python33\Lib\urllib\request.py", line 447, in _call_chain
result = func(*args)
File "C:\Python33\Lib\urllib\request.py", line 1268, in http_open
return self.do_open(http.client.HTTPConnection, req)
File "C:\Python33\Lib\urllib\request.py", line 1248, in do_open
h.request(req.get_method(), req.selector, req.data, headers)
File "C:\Python33\Lib\http\client.py", line 1061, in request
self._send_request(method, url, body, headers)
File "C:\Python33\Lib\http\client.py", line 1089, in _send_request
self.putrequest(method, url, **skips)
File "C:\Python33\Lib\http\client.py", line 953, in putrequest
self._output(request.encode('ascii'))
UnicodeEncodeError: 'ascii' codec can't encode character '\xe9' in position 13: ordinal not in range(128)
任何幫助表示贊賞這讓我發瘋,我想我已經嘗試了 x.decode 和類似的所有組合
(如果可能的話,我可以忽略有問題的字符。)
使用百分比編碼的 URL :
link = 'http://finance.yahoo.com/news/caf%C3%A9s-growing-faster-than-fast-food-peers-144512056.html'
我通過將瀏覽器指向了上面的百分比編碼的 URL
http://finance.yahoo.com/news/cafés-growing-faster-than-fast-food-peers-144512056.html
轉到頁面,然后將瀏覽器提供的編碼 URL 復制並粘貼回文本編輯器。 但是,您可以使用以下方法以編程方式生成百分比編碼的 URL:
from urllib import parse
link = 'http://finance.yahoo.com/news/cafés-growing-faster-than-fast-food-peers-144512056.html'
scheme, netloc, path, query, fragment = parse.urlsplit(link)
path = parse.quote(path)
link = parse.urlunsplit((scheme, netloc, path, query, fragment))
這產生
http://finance.yahoo.com/news/caf%C3%A9s-growing-faster-than-fast-food-peers-144512056.html
您的 URL 包含無法表示為 ASCII 字符的字符。
您必須確保所有字符都經過正確的 URL 編碼; 例如使用urllib.parse.quote_plus
; 它將使用 UTF-8 URL 編碼轉義來表示任何非 ASCII 字符。
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