[英]Page breaks only once
我有一個PHP / HTML頁面,上面打印出許多收據。 我試圖在每次實際打印后使其分頁。 我已經嘗試了幾種樣式和類代碼,但是我能做的最好的事情是讓它在第一個代碼之后就中斷了,但是永遠不會重復。 IOW,我希望它每次打印代碼中引用的表后都能分頁。
enter code here
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html><head>
<style type="text/css">
@media all {
.page-break { display: none; }
}
@media print {
.page-break { display: block; page-break-before: always; }
}
</style>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
<title>North Atlanta Riding Club</title>
<link href="../styles.css" rel="stylesheet" type="text/css">
<style type="text/css">
<!--
.style45 {
color: #FF0000;
font-weight: bold;
font-style: italic;
}
-->
</style>
</head>
<body>
<?php
do{
//THIS SEES IF THE LOGGED IN MEMBER HAS CONFIRMED CLOTHING
$colname_confirmed = "1";
if (isset($row_roster['key1'])) {
$colname_confirmed = (get_magic_quotes_gpc()) ? $row_roster['key1'] : addslashes($row_roster['key1']);
}
mysql_select_db($database_connection1, $connection1);
$query_confirmed = sprintf("SELECT * FROM clothingorder WHERE who = %s AND confirmed = 'Y' ORDER BY key1 ASC", $colname_confirmed);
$confirmed = mysql_query($query_confirmed, $connection1) or die(mysql_error());
$row_confirmed = mysql_fetch_assoc($confirmed);
$totalRows_confirmed = mysql_num_rows($confirmed);
if($totalRows_confirmed<>0){?>
<table width="990" border="0" align="left" cellpadding="0" cellspacing="0">
<!--DWLayoutTable-->
<tr>
<td width="990" height="31" valign="top"><!--DWLayoutEmptyCell--> </td>
</tr>
<tr>
<td height="83" valign="top">
<table border="1" align="left" cellpadding="2" cellspacing="0" bordercolor="#000000">
<tr bgcolor="#FFFFFF" class="style5">
<td colspan="9"><p>Member- <strong><?php echo $row_roster['fname']." ".$row_roster['lname']; ?><br>
</strong>Telephone- <strong><?php echo $row_roster['tel']; ?></strong> Email- <strong><?php echo $row_roster['email']; ?></strong><br>
Address- <br>
<strong>
<?php if($row_roster['add1']<>''){echo $row_roster['add1']."<br>";} ?>
</strong>
<strong>
<?php if($row_roster['add2']<>''){echo $row_roster['add2']."<br>";} ?>
</strong>
<strong>
<?php if($row_roster['city']<>''){echo $row_roster['city'].", ";} ?>
</strong>
<strong>
<?php if($row_roster['state']<>''){echo $row_roster['state']." ";} ?>
</strong>
<strong>
<?php if($row_roster['zip']<>''){echo $row_roster['zip'];} ?>
</strong><br>
</p>
</td>
</tr>
<tr bgcolor="#FFFFFF" class="style5">
<td><div align="center"><strong>Qty</strong></div></td>
<td><strong>Item</strong></td>
<td><strong>PO?</strong></td>
<td><div align="center"><strong>Paid?</strong></div></td>
<td><div align="center"><strong>Mens/Womens</strong></div></td>
<td><div align="center"><strong>Style</strong></div></td>
<td><div align="center"><strong>Cut</strong></div></td>
<td><div align="center"><strong>Size</strong></div></td>
<td><div align="center"><strong>Price</strong></div></td>
</tr>
<tr bgcolor="#FFFFFF" class="style5">
<td colspan="8"><div align="right">Narc Membership </div></td>
<td><div align="center">
<?php if($row_roster['paid']=="Y"){echo "Paid";$total=0;}else{echo "$".$row_dues['dues'];$total=$row_dues['dues'];} ?></div></td>
</tr>
<?php
do {
$colname_item = "1";
if (isset($row_confirmed['item'])) {
$colname_item = (get_magic_quotes_gpc()) ? $row_confirmed['item'] : addslashes($row_confirmed['item']);
}
mysql_select_db($database_connection1, $connection1);
$query_item = sprintf("SELECT key1, item, price, free FROM clothing WHERE key1 = %s", $colname_item);
$item = mysql_query($query_item, $connection1) or die(mysql_error());
$row_item = mysql_fetch_assoc($item);
$totalRows_item = mysql_num_rows($item);
?>
<tr class="style5">
<td><div align="center"><?php echo $row_confirmed['qty']; ?></div></td>
<td><?php echo $row_item['item']; ?></td>
<td><div align="center"><span class="style45">
<?php if($row_confirmed['postorder']=='Y'){?>YES<?php }?></span></div></td>
<td><div align="center"><?php echo $row_confirmed['paid']; ?></div></td>
<td><div align="center"><?php echo $row_confirmed['mf']; ?></div></td>
<td><div align="center"><?php echo $row_confirmed['style']; ?></div></td>
<td><div align="center"><?php echo $row_confirmed['cut']; ?></div></td>
<td><div align="center"><?php echo $row_confirmed['size']; ?></div></td>
<td><div align="center">
<?php if($row_confirmed['price'] == 0){echo "Free";
}else{
if($row_confirmed['paid']=="Y"){echo "Paid";}else{echo $row_confirmed['price'];$total = $total + $row_confirmed['price'];}
} ?>
</div></td>
</tr>
<?php
} while ($row_confirmed = mysql_fetch_assoc($confirmed)); ?>
<tr bgcolor="#FFFFFF" class="style5">
<td colspan="8"><div align="right"><em><strong>Total Owed</strong></em></div></td>
<td><div align="center" class="style6"><em><strong><?php echo "$".$total.".00";?></strong></em></div></td>
</tr>
</table>
</td>
</tr>
</table>
<div class="page-break"></div>
<?php
}
}while($row_roster = mysql_fetch_assoc($roster));
?>
</body>
我也發現@media print {}中的分頁符“不可靠”! 實際上,到目前為止,發現@media打印完全不完整。 浮動效果不好,似乎沒有按照預期顯示幾個樣式細節。 似乎瀏覽器對“打印”的支持不佳。 我正在開發一個應打印姓名徽章的應用程序,而精度對於放置和調整大小至關重要。 我希望放棄@media印刷版{}樣式,盡管我希望它看起來像網絡版,但可以按照我的設想進行印刷。 可能需要像徽章一樣解決它。 我正在使用的代碼每6條“記錄”添加分頁符class div(徽章在3、4“ x 3” w的2列中為6-up)。
如果像我一樣,您找不到使用@media print {}的方法,將其僅打印在打算打印的收據上會起作用嗎? 直到(如果有)瀏覽器趕上w3c約定之前,也可能是您的解決方法。 我很想找到一個好的出版物來解釋@media印刷樣式的作用和不作用,否則屏幕樣式應該起作用。
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