不同的行來自一列。 甲骨文

Question

我想基於運算符顯示不同的行。 喜歡

$query = oci_parse($con, "SELECT POST.*, USER_LOGIN.*, STATION.*, ROLE.* 
                          FROM USER_LOGIN 
                          INNER JOIN STATION ON USER_LOGIN.S_ID = STATION.S_ID
                          INNER JOIN POST ON USER_LOGIN.USER_ID = POST.USER_ID
                          INNER JOIN ROLE ON USER_LOGIN.ROLE_ID = ROLE.ROLE_ID
                          WHERE ROLE_NAME = 'Operator' "); 

任何幫助，將不勝感激。

我現在得到以下錯誤。 我不知道這是怎么回事。

Error: ORA-00936: missing expression

$query = oci_parse($con,"SELECT * FROM 

        (SELECT POST.*, USER_LOGIN.*, STATION.*, ROLE.*, IR.*,
        row_number() over(PARTITION BY ROLE_NAME ORDER BY ROLE_NAME) AS seqnum

        FROM USER_LOGIN

        INNER JOIN
        STATION
        ON USER_LOGIN.PS_ID = STATION.PS_ID

        INNER JOIN
        POST
        ON USER_LOGIN.USER_ID = POST.USER_ID

        INNER JOIN
        ROLE
        ON USER_LOGIN.ROLE_ID = ROLE.ROLE_ID

        INNER JOIN
        IR
        ON USER_LOGIN.USER_ID = IR.USER_ID

        WHERE ROLE_NAME = 'Operator') AS t

        WHERE t.seqnum = 1");

Answer 1

我的猜測是您想指定特定的列並使用distinct （或group by ）：

SELECT DISTINCT operator, cnic, station 
FROM USER_LOGIN INNER JOIN
     STATION
     ON USER_LOGIN.S_ID = STATION.S_ID INNER JOIN
     POST
     ON USER_LOGIN.USER_ID = POST.USER_ID INNER JOIN
     ROLE
     ON USER_LOGIN.ROLE_ID = ROLE.ROLE_ID
WHERE ROLE_NAME = 'Operator';

編輯：

如果要任意行，請執行以下操作：

SELECT *
FROM (SELECT POST.*, USER_LOGIN.*, STATION.*, ROLE.*,
             row_number() over (partition by operator, cnic, station order by operator) as seqnum
      FROM USER_LOGIN INNER JOIN
           STATION
           ON USER_LOGIN.S_ID = STATION.S_ID INNER JOIN
           POST
           ON USER_LOGIN.USER_ID = POST.USER_ID INNER JOIN
           ROLE
           ON USER_LOGIN.ROLE_ID = ROLE.ROLE_ID
      WHERE ROLE_NAME = 'Operator'
     ) t
WHERE seqnum = 1;

row_number()函數枚舉組中的行。 每個組都從1開始。分組是通過partition by定義的，因此具有operator ， cnic和station相同值的行將在分組中。 order by指定組中數字的順序。 這里為組使用一個常量，因此它是任意的。 最后一步是where seqnum = 1 ，它從每個分組中選擇一行。

Answer 2

來自： http : //docs.oracle.com/cd/B28359_01/server.111/b28286/statements_10002.htm#SQLRF55166

如果希望數據庫僅返回所選的每組重復行的一個副本，則指定DISTINCT或UNIQUE。

像這樣更新您的代碼：

$query = oci_parse($con, "SELECT DISTINCT  POST.*, USER_LOGIN.*, STATION.*, ROLE.* 
    FROM USER_LOGIN 
    INNER JOIN STATION ON USER_LOGIN.S_ID = STATION.S_ID
    INNER JOIN POST ON USER_LOGIN.USER_ID = POST.USER_ID
    INNER JOIN ROLE ON USER_LOGIN.ROLE_ID = ROLE.ROLE_ID
    WHERE ROLE_NAME = 'Operator' ");