[英]Show/Hide table header using jQuery
遍歷每個項目時,基本上基於表的內容,我有兩種不同類型的標題:
JS代碼:
if (idLayer == "nss") {
var tabs = [];
for (var layerId in layers) {
var results = layers[layerId];
idResults[idLayer + layerId] = results;
var useHeaderComm = false;
var count = results.length;
var label = "", content = "";
var resultsId = idLayer + layerId;
switch (layerId) {
case "2":
label = "New Sale Sites(" + count + ")";
if (count == 0) break;
content += "<table><tr id='headerComm'><th>Location</th><th>Planning Area</th><th>Development Type</th><th>GPR</th><th>Site Area</th><th>Allowable GFA</th><th>Office GFA</th><th>Retail GFA</th><th>Other GFA</th></tr>";
content += "<table><tr id='headerResi'><th>Location</th><th>Planning Area</th><th>Development Type</th><th>GPR</th><th>Site Area</th><th>Estimated DU</th></tr>";
for (var j = 0; j < count; j++) {
if (latlng !== 'Null') {
var attributes = results[j].feature.attributes;
var resultsId = idLayer + layerId;
if(attributes["LAND_USE"] == "COMM" || attributes["LAND_USE"] == "OFF" )
{
content += "<tr>";
content += "<td><a href='javascript:void(0)' onclick='showFeature(\"" + resultsId + "\"," + j + ")'>" + attributes["LOCATION"] + "</a></td>";
content += "<td>" + attributes["PLANNING_AREA"] + "</td>";
content += "<td>" + attributes["LAND_USE"] + "</td>";
if(attributes["GPR"] != "Null" && attributes["GPR"] != "" && attributes["GPR"] != undefined && attributes["GPR"] != "null")
{
content += "<td>" + attributes["GPR"] + "</td>";
}
else
{
content += "<td>N.A</td>";
}
content += "<td>" + attributes["SITE_AREA"] + "</td>";
content += "<td>" + attributes["ALLOWABLE_GFA"] + "</td>";
content += "<td>" + attributes["OFFICE_GFA"] + "</td>";
content += "<td>" + attributes["RETAIL_GFA"] + "</td>";
content += "<td>" + attributes["HOTEL_GFA"] + "</td>";
content += "</tr>";
useHeaderComm = true;
}else
{
content += "<tr>";
content += "<td><a href='javascript:void(0)' onclick='showFeature(\"" + resultsId + "\"," + j + ")'>" + attributes["LOCATION"] + "</a></td>";
content += "<td>" + attributes["PLANNING_AREA"] + "</td>";
content += "<td>" + attributes["LAND_USE"] + "</td>";
if(attributes["GPR"] != "Null" && attributes["GPR"] != "" && attributes["GPR"] != undefined && attributes["GPR"] != "null")
{
content += "<td>" + attributes["GPR"] + "</td>";
}
else
{
content += "<td>N.A</td>";
}
content += "<td>" + attributes["SITE_AREA"] + "</td>";
if(attributes["ESTIMATED_DU"] != "Null" && attributes["ESTIMATED_DU"] != "" && attributes["ESTIMATED_DU"] != undefined && attributes["ESTIMATED_DU"] != "null")
{
content += "<td>" + attributes["ESTIMATED_DU"] + "</td>";
}
else
{
content += "<td>N.A</td>";
}
content += "</tr>";
useHeaderComm = false;
}
}
if(useHeaderComm == true)
{
$('.headerResi').hide();
}else
{
$('.headerComm').hide();
}
}
content += "</table>";
break;
}
}
}
我想做的是遍歷結果中的每個項目,並根據某些屬性顯示表頭。
例如,如果LAND_USE
是"COMM"
或"OFF"
則使用的表頭應該是id為headerComm
tr
。
但是,對於這些代碼,兩個標題都只是顯示而沒有隱藏或顯示。 我不知道為什么會這樣。
我認為您正在為<tr>
使用id,因此,您的代碼應該是
if(useHeaderComm == true)
{
$('#headerResi').hide();
}
else
{
$('#headerComm').hide();
}
還有一件事。 您無需在此代碼中兩次添加另一個<table>
,
content += "<table><tr id='headerComm'><th>Location</th><th>Planning Area</th><th>Development Type</th><th>GPR</th><th>Site Area</th><th>Allowable GFA</th><th>Office GFA</th><th>Retail GFA</th><th>Other GFA</th></tr>";
content += "<table><tr id='headerResi'><th>Location</th><th>Planning Area</th><th>Development Type</th><th>GPR</th><th>Site Area</th><th>Estimated DU</th></tr>";
它應該是,
content += "<table><tr id='headerComm'><th>Location</th><th>Planning Area</th><th>Development Type</th><th>GPR</th><th>Site Area</th><th>Allowable GFA</th><th>Office GFA</th><th>Retail GFA</th><th>Other GFA</th></tr>";
content += "<tr id='headerResi'><th>Location</th><th>Planning Area</th><th>Development Type</th><th>GPR</th><th>Site Area</th><th>Estimated DU</th></tr>";
這是因為在執行條件時,不會將元素附加到DOM中。 jQuery僅在DOM或創建的元素中搜索。
我建議將其附加到DOM后檢查要顯示的1:
$(selector).append(content);
if(useHeaderComm == true)
{
$('.headerResi').hide();
}else
{
$('.headerComm').hide();
}
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