[英]How do I remove the first node in a linked list with a remove method
我想創建一個鏈表,然后用1-100填充它。 之后,我打印出所有的偶數,而沒有實際從列表中刪除奇數,然后再次打印出偶數,但是將它們加倍。 完成這些操作后,我從鏈接列表中刪除了奇數並打印出列表。 我提到的最后一步是掛斷電話。 其他一切工作正常,只是我的remove方法刪除了除1以外的所有奇數。在我的主要方法中,我使用了if語句,該語句說如果節點%2中包含的數字等於零,則刪除該節點。 它適用於除第一個節點以外的每個節點。 謝謝你們給我的任何幫助。 我的代碼如下。
import java.util.*;
/*
* My ListNode class
*/
class ListNode<Integer> {
private Integer item;
private ListNode<Integer> next;
public ListNode(Integer item) {
this.item = item;
next = null;
}
public ListNode(Integer item, ListNode<Integer> next) {
this.item = item;
this.next = next;
}
public Integer getItem() {
return item;
}
public ListNode<Integer> getNext() {
return next;
}
public void setItem(Integer item) {
this.item = item;
}
public void setNext(ListNode<Integer> next) {
this.next = next;
}
}
/*
* My LinkedList class
*/
class LinkedList<Integer> {
public ListNode<Integer> front;
public LinkedList() {
front = null;
}
public boolean isEmpty() {
return front == null;
}
public boolean contains(int target) {
for (ListNode<Integer> node = front;
node != null;
node = node.getNext()) {
if (node.getItem().equals(target)) {
return true;
}
}
return false;
}
public int size() {
int count = 0;
for (ListNode<Integer> node = front;
node != null;
node = node.getNext()) {
count++;
}
return count;
}
public String toString() {
String result = "( ";
for (ListNode<Integer> node = front;
node != null;
node = node.getNext()) {
result += node.getItem() + " ";
}
return result + ")";
}
public Integer get(int index) {
ListNode<Integer> node = front;
for (int i = 0; i < index; i++) {
node = node.getNext();
}
return node.getItem();
}
public void set(int index, Integer target) {
ListNode<Integer> node = front;
for (int i = 0; i < index; i++) {
node = node.getNext();
}
node.setItem(target);
}
public void add(int index, int target) {
if (isEmpty()) {
front = new ListNode(target);
} else {
ListNode last = front;
while (last.getNext() != null) {
last = last.getNext();
}
last.setNext(new ListNode(target));
}
}
public Integer remove(int index) {
ListNode<Integer> node = front;
ListNode<Integer> prev = front;
for (int i = 0; i < index; i++) {
prev = node;
node = node.getNext();
}
prev.setNext(node.getNext());
return node.getItem();
}
}
public class LinkedListTest {
//interface Removal {
//Integer remove (Integer item);
//}
public static void main(String[] args) {
LinkedList<Integer> list = new LinkedList<Integer>();
System.out.println(list);
System.out.println("The list size is " + list.size());
System.out.println();
/*
* This adds the numbers 1 through 100 to a LinkedList
*/
for (int i = 1; i <= 100; i++)
list.add(0, i);
System.out.println(list);
System.out.println("The list size is " + list.size());
System.out.println();
/*
* This prints out only even numbers by excluding indexes that are even,
* because all the even numbers are held in the odd numbered indexes, thus
* index 0 is 1 but index 1 is 2, index 3 is 4
*/
for (int i = 0; i < list.size(); i++)
if (i % 2 == 1) {
System.out.print(list.get(i) + " ");
}
System.out.println();
System.out.println("The list size is " + list.size());
System.out.println();
/*
* This doubles even numbers
*/
for (int i = 0; i < list.size(); i++)
if (i % 2 == 1) {
int result = list.get(i) * 2;
System.out.print(result + " ");
}
System.out.println();
System.out.println("The list size is " + list.size());
System.out.println();
for (int i = 0; i < list.size(); i++)
if (list.get(i) % 2 == 1) {
list.remove(i);
}
System.out.print(list);
System.out.println();
System.out.println("The list size is " + list.size());
System.out.println();
/*
* These contain methods only work for the first list created
*/
System.out.println("Does the list contain 32? " + list.contains(32));
System.out.println("Does the list contain 33? " + list.contains(33));
}
}
當index
值為0
時, remove
方法實際上不起作用。.因為i<index
條件為false,所以您的node
和prev
都被初始化為front
並且未執行循環。 因此,對於index=0
的情況,您必須添加另一個條件。在remove
方法的開頭添加這些行即可解決此問題。
if(index==0){
ListNode<integer>temp=front;
front=front.getNext();
return temp.getItem();
}
希望它能幫助...
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