[英]PHP - IF doesn't check if the condition is true
我正在根據用戶輸入的動詞結尾創建動詞共軛詞。
現在,它應該對以“ aic”,“ eic”,“ oic”(一個尾數數組)和“ bic”,“ fic”,“ mic”,“ nic”,“ pic”和“ wic”結尾的動詞起作用(另一組結尾)。
不幸的是,它一直將第一個數組分配給我放置的任何內容-即使它沒有以指定的結尾結尾。
這是頁面:www.alweso.2ap.pl/koniugator/index.php
這是代碼:
<?php
$verb = $_POST["verb"];
$last2 = substr ($verb, -2);
$last3 = substr($verb, -3);
$last4 = substr($verb, -4);
$last5 = substr($verb, -5);
$last6 = substr($verb, -6);
$last7 = substr($verb, -7);
$last8 = substr($verb, -8);
$last9 = substr($verb, -9);
$root2 = str_replace($last2, "", $verb);
$root3 = str_replace($last3, "", $verb);
$root4 = str_replace($last4, "", $verb);
$root5 = str_replace($last5, "", $verb);
$root6 = str_replace($last6, "", $verb);
$root7 = str_replace($last7, "", $verb);
$root8 = str_replace($last8, "", $verb);
$root9 = str_replace($last9, "", $verb);
$aic_eic_oic = array("je", "isz", "i", "imy", "icie", "ja" );
$bic_fic_mic_nic_pic_wic = array("ie", "isz", "i", "imy", "icie", "ia" );
$cic_lic_sic_zic = array("e", "isz", "i", "imy", "icie", "a" );
?>
<div class="container">
<div class="row">
<div class="col-md-4 col-md-offset-4">
<?php
if ($last3 == ("aic" || "eic" || "oic")) {
foreach ($aic_eic_oic as $one) {
echo "<li>$root2$one</li>";
}
}
elseif ($last3 == ("bic" || "fic" || "mic" || "nic" || "pic" || "wic")) {
foreach ($bic_fic_mic_nic_pic_wic as $one) {
echo "<li>$root2$one</li>";
}
}
?>
</div>
</div>
</div>
你不能做if($value = ($a || $b || $c))
做if(in_array($value, array($a, $b, $c))
。 if($value = ($a || $b || $c))
意思是: $value == true
,因為'foo' || 'bar' || 'barfoo'
被評估為true(在PHP中非空字符串始終為true)。
誰告訴你那行得通? 你在哪里讀的? 那沒有任何文檔。 它不是那樣工作的。
if( in_array($last3, array("aic","eic","oic")))
// ...
elseif( in_array($last3, array("bic","fic","mic","nic","pic","wic")))
或者:
switch($last3) {
case "aic":
case "eic":
case "oic":
// do something
break;
case "bic":
case "fic":
case "mic":
case "nic":
case "pic":
case "wic":
// do something else
break;
default:
// optional, do something to indicate error
}
您的if語句語法不正確,您不能執行if($last3 == (x || y || z))
因為它不合邏輯,該語句讀取`if($ last3 ==(x == true || y == true || z == true))
您必須將其完整寫出:
if ($last3 == x || $last3 == y || $last3 ==z)
或使用in_array()
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