使用bash腳本並使用case語句

Question

我正在嘗試創建一個bash命令，在其中輸入1到12之間的數字，並且它使用switch命令，但是在bash shell中是case命令。 我只需要確保我有正確的想法就可以了，否則我將無法完成

#!/bin/bash
1="January"
2="February"
3="March"
4="April"
5="May"
6="June"
7="July"
8="August"
9="September"
10="October"
11="November"
12="December"
case "1" in
print "$1"
case "2" in
print "$2" 
case "3" in
print "$3"
case "4" in
print "$4"
case "5" in
print "$5"
case "6" in
print "$6"
case "7" in
print "$7"
case "8" in
print "$8"
case "9" in
print "$9"
case "10" in
print "$10"
case "11" in
print "$11"
case "12" in 
print "$12"
echo "Please enter a number 1 through 12"
read input_variable
echo "$input_variable"

Answer 1

恐怕你有點不滿意。 這有點像它：

#!/bin/bash

echo "Please enter a number 1 through 12"
read input_variable

case $input_variable in
    1) 
        echo "January"
        ;;
    2) 
        echo "February"
        ;;
    3) 
        echo "March"
        ;;
    4) 
        echo "April"
        ;;
  # 5), 6) etc.
    *) # anything else
        echo "not recognised" 
        ;;
esac

@Charles Duffy是正確的，您實際上不需要這種case 。 您可以改用如下數組：

編輯 ：當我寫這篇文章，我看到@devnull的改進！

#!/bin/bash

echo "Please enter a number 1 through 12"
read input

months=( January February March April May June July August September October November December )

[ $input -gt 0 -a $input -le 12 ] && echo "${months[input-1]}"

或者，如果願意，在數組的開頭使用一個虛擬條目（感謝@chepner）

months=( "" January February March April May June July August September October November December )

[ ! -z "${months[input]}" ] && echo "${months[input]}"

Answer 2

采用：

read -p "Enter a number between 1 and 12: " input

因為它簡化了代碼。 然后使用：

case $input in 

...如湯姆·費內奇所說

但是，是的，case語句更多地用於針對相同類型的結果進行測試，但是要根據結果來執行不同的操作。 您在這里回顯所有內容，所以是的，將字符串存儲在數組中，然后根據輸入將其輸出。