Spring 3 \\ Quartz2。集成問題

Question

我在整合彈簧和石英方面遇到問題。 我需要將CronTriggerFactoryBean動態添加到SchedulerFactoryBean 。

XML Spring映射：

<bean class="org.springframework.scheduling.quartz.SchedulerFactoryBean" scope="prototype">
    <property name="jobDetails">
        <list>
            <ref bean="plannedVacationServiceJob" />
        </list>
    </property>
    <property name="triggers">
        <list>
            <ref bean="plannedVacationServiceCronTrigger" />
        </list>
    </property>
</bean>

<bean id="plannedVacationServiceJob" class="org.springframework.scheduling.quartz.JobDetailFactoryBean">
    <property name="jobClass" value="com.my.service.package.PlannerJob" />
    <property name="durability" value="true" />
</bean>

<bean id="plannedVacationServiceCronTrigger" class="org.springframework.scheduling.quartz.CronTriggerFactoryBean" scope="prototype">
    <property name="jobDetail" ref="plannedVacationServiceJob" />
    <property name="cronExpression" value="*/15 * * * * ?" />
</bean>

Java代碼：

@Service
public class Planner implements Planning { 
@Autowired
@Qualifier("plannedVacationServiceCronTrigger")
private CronTriggerFactoryBean plannedVacationServiceCronTrigger;

@Autowired
private SchedulerFactoryBean schedulerFactoryBean;

 @PostConstruct
 public void init() {
       schedulerFactoryBean.start();
 } 
//some code 
private void addTask(PlannerEntity entity) {
    try {
        String name = getIdentityName(entity);
        JobKey jobKey = new JobKey(name);
        String cronExpression = getCronExpression(entity);
        plannedVacationServiceCronTrigger.setCronExpression(cronExpression);
        JobDetail jobDetail =      JobBuilder.newJob(PlannerJob.class).withIdentity(jobKey).build();
        plannedVacationServiceCronTrigger.setJobDetail(jobDetail);
        plannedVacationServiceCronTrigger.setName(name);
        plannedVacationServiceCronTrigger.afterPropertiesSet();
        schedulerFactoryBean.getScheduler().scheduleJob(jobDetail, plannedVacationServiceCronTrigger.getObject());
        triggers.put(entity.getId(), trigger);
    } catch (Exception e) {
        e.printStackTrace();
    }
}
}

在這種情況下，我們只有一個觸發器，該觸發器已添加到xml映射中

我嘗試從xml刪除對觸發器的引用，並從代碼創建CronTriggerFactoryBean：

private void addTask(PlannerEntity entity) {
    try {
        String name = getIdentityName(entity);
        JobKey jobKey = new JobKey(name);
        String cronExpression = getCronExpression(entity);
        CronTriggerFactoryBean trigger = new CronTriggerFactoryBean();
        trigger.setCronExpression(cronExpression);
        JobDetail jobDetail = JobBuilder.newJob(PlannerJob.class).withIdentity(jobKey).build();
        trigger.setJobDetail(jobDetail);
        trigger.setName(name);
        trigger.afterPropertiesSet();
        schedulerFactoryBean.getScheduler().scheduleJob(jobDetail, trigger.getObject());
        triggers.put(entity.getId(), trigger);
    } catch (Exception e) {
        e.printStackTrace();
    }
}

但是在這種情況下，我們沒有任何觸發器：

2014-04-02 14:28:55,144 DEBUG [org.quartz.core.QuartzSchedulerThread(org.springframework.scheduling.quartz.SchedulerFactoryBean#0_QuartzSchedulerThread)] - batch acquisition of 0 triggers
2014-04-02 14:29:18,981 DEBUG [org.quartz.core.QuartzSchedulerThread(org.springframework.scheduling.quartz.SchedulerFactoryBean#0_QuartzSchedulerThread)] - batch acquisition of 0 triggers
2014-04-02 14:29:46,361 DEBUG [org.quartz.core.QuartzSchedulerThread(org.springframework.scheduling.quartz.SchedulerFactoryBean#0_QuartzSchedulerThread)] - batch acquisition of 0 triggers
2014-04-02 14:30:09,439 DEBUG [org.quartz.core.QuartzSchedulerThread(org.springframework.scheduling.quartz.SchedulerFactoryBean#0_QuartzSchedulerThread)] - batch acquisition of 0 triggers

Answer 1

你真的不能那樣做。 FactoryBean有一個特定的合同，您正在嘗試在其中執行。

工廠bean是旨在以編程方式創建bean的bean。 您不能真正注入工廠bean，因為它存在的唯一目的是注冊一個bean。 此外， start回調與應用程序上下文生命周期有關。 當您從代碼中調用它時，為時已晚，調度程序已處於活動狀態。

初始化bean時將注冊觸發器（在afterPropertiesSet回調方法中）。 如果在此之后嘗試向工廠添加其他觸發器，則由於已創建調度程序，因此不會將其考慮在內。

話雖如此，我真的看不到XML和Java代碼之間的關系。 在常規情況下，應該注冊您的plannedVacationServiceCronTrigger （沒有理由制作prototype bean）。