[英]MySQL select data from table and inner join the union all selection from another two identical tables
[英]Get data from two tables using UNION ALL
我有三個表:類別和Deals1和Deals2。
我有下一個mySQL句子,它可以正常工作:
SELECT name,
(SELECT categoria FROM categorias WHERE categorias.id = deals.id) AS categoria
from deals1 where id = '1'
但是現在,我需要使用UNION ALL來從兩個不同的表中獲取數據……
(SELECT name,
(SELECT categoria FROM categorias WHERE categorias.id = deals1.id) AS categoria
from deals1 where id = '1')
UNION ALL
(SELECT name,
(SELECT categoria FROM categorias WHERE categorias.id = deals2.id) AS categoria
from deals2 where id = '1')
它返回錯誤。。。。
非常感謝!
編輯:我發現了問題...
在我的項目中,我有:
... SELECT categoria FROM categorias WHERE categorias.id = **deals2.id**) AS categoria
from **deals1** where id = '1')
下一個是正確的句子...如果您注意的話,您將看到差異(強詞)...
(SELECT name,
(SELECT categoria FROM categorias WHERE categorias.id = **deals2.id**) AS categoria
from **deals2** where id = '1')
謝謝大家!
語法看起來正確,唯一讓我困擾的是括號:
我查詢的語法始終是:
SELECT name,
(SELECT categoria FROM categorias WHERE categorias.id = deals1.id) AS categoria
from deals1 where id = '1'
UNION ALL
SELECT name,
(SELECT categoria FROM categorias WHERE categorias.id = deals2.id) AS categoria
from deals2 where id = '1';
沒有外部括號...
請注意-子選擇項中的表格應為Deals1 / Deals2-而非交易。
但是-您遇到的錯誤是什么?
另外,您是否要使用全部工會或工會(您希望同一結果出現一次還是多次?)? 工會還將通過措辭添加一個隱含的“區別”-我想您是希望的,但是我不確定(所有聯合會只是將結果連接起來,如果產生相同的記錄則結果會重復)
首先檢查表的名稱,您說的是它的Deals1和Deals2,但是將所有第一個查詢合並
(SELECT name,
(SELECT categoria FROM categorias WHERE categorias.id = deals.id) AS categoria
from deals where id = '1')
它的“交易”。
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