[英]get index of object in array in object in array
與游戲引擎Impactjs一起使用時,此處和關卡的設置非常奇怪:
[
{
"entities": [
{"type":"type1","x":100,"y":100,"settings":{"directsTo":"-5"}},
{"type":"type2","x":101,"y":101,"settings":{"directsTo":"-4"}}
],
"layer": [
other data
]
}
]
我想知道如何根據設置對象的directsTo屬性獲取type1對象的索引?
Javascript或jQuery都可以。
編輯:游戲必須在移動設備上流暢運行,因此擁有高效的解決方案是不錯的。
嘗試這個,
var arr =[{
"entities": [{
"type": "type1",
"x": 100,"y": 100,
"settings": {"directsTo": "-5"}
}, {
"type": "type2",
"x": 101,"y": 101,
"settings": {"directsTo": "-4"}
}],
"layer": ['other data']
}];
var t='type1';
var newArr=arr[0];
for(var data in newArr){
for(a in newArr[data]){
if(newArr[data][a].type == t){
alert('Index of '+t+' is '+a+' in '+data);
}
}
}
您可以使用filter
屬性嗎?
假設您的JS對象看起來像這樣
var j = [
{
"entities": [
{"type":"type1","x":100,"y":100,"settings":{"directsTo":"-5"}},
{"type":"type2","x":101,"y":101,"settings":{"directsTo":"-4"}}
],
"layer": [
"otherdata":{}
]
}
];
您可以使用找到對象
var result = j[0].entities.filter(function(n) { return n.settings.directsTo == "-5"; });
// result[0].type == "type1"
您可以創建一個函數來獲取其他對象之間的對象索引,例如這樣
//assuming you have the data parsed as a JSON object "data"
//and you also have your entity object as "obj"
function getIndex(obj, data){
return data.entities.indexOf(obj);
}
如果沒有“ obj”對象,則必須創建一個函數,該函數首先根據屬性(例如類型參數)找到正確的對象
function findEntity(type, source){
for(var i=0; i<source.entities.length; i++){
if(source.entities[i].type == type){
return source.entities[i];
}
}
return false;
}
現在你可以這樣稱呼它
getIndex(findEntity("type1", data), data);
希望它可以幫助您開始!
感謝Rohan Kumar和ВикторНовиков。
var array =[
{
"entities": [
{
"type": "type1",
"x": 100,"y": 100,
"settings": {"directsTo": "-5"}
},
{
"type": "type2",
"x": 101,"y": 101,
"settings": {"directsTo": "-4"}
}
],
"layer": ['other data']
}
];
function getArrayIndexForLocationKey(arr, val) {
for(var i = 0; i < arr.length; i++){
if(arr[i].settings.directsTo == val)
return i;
}
return -1;
}
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