[英]Php update query not working
這段代碼具有一種形式,當使用單擊提交時,我試圖更新數據庫,但是由於某種原因,我不知道我的更新查詢無法正常工作,這段代碼檢測到錯誤
catch(PDOException $ex)
{
die("Error");
}
有關如何解決此問題的任何想法
if(empty($_SESSION['user']))
{
header("Location: index.php");
die("Redirecting to index.php");
}
if(!empty($_POST))
{
if(empty($_POST['name']))
{
die("Enter a name");
}
$query = "SELECT 1 FROM courses WHERE name = :name";
$query_params = array(':name' => $_POST['name']);
try
{
$stmt = $db->prepare($query);
$result = $stmt->execute($query_params);
}
catch(PDOException $ex)
{
die("Error 1");
}
$row = $stmt->fetch();
if($row)
{
die("Same Name");
}
$nombre = $_SESSION['user']['username'];
$name = $_POST['name'];
$query = "UPDATE courses SET name = '$name' WHERE id = 1)";
try
{
$stmt = $db->prepare($query);
$stmt->execute();
}
catch(PDOException $ex)
{
die("Error");
}
header("Location: index.php");
die("Redirecting to index.php");
}
?>
<?php
foreach($rows as $row):
echo '<form action="mod.php" method="post">';
echo '<input type="text" name="name" value="' .htmlentities($row['name']) . '" />';
echo '<input type="submit" value="submit">';
echo '</form>';
endforeach;
$query = "UPDATE courses SET name = '$name' WHERE id = 1";
最后有一個括號。
$query = "UPDATE courses SET name = '$name' WHERE id = 1)";
^---- Here
正如Gerald Schneider在此評論中提到的,請進行更改,以便您可以輕松跟蹤錯誤。
確保通過以下方式放置PHP變量:
$query = "UPDATE courses SET name = '".$name."' WHERE id = 1";
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