在紅寶石中分類哈希的最有效方法是什么？

Question

我正在嘗試根據數組的屬性之一對紅寶石中的20種哈希進行排序。 我只想返回前3個散列鍵 ，但是我不想比較每個散列鍵 。

這是下面的示例，類似於我要排序的內容。 我想根據powerrank排序。

["green", {:price=>24.88, :numreviews=>822, :avgStarsRank=>41.0, :reviewsrank=>28, :powerrank=>73.976}]

["steve", {:price=>14.96, :numreviews=>3, :avgStarsRank=>40.0, :reviewsrank=>0, :powerrank=>42.992000000000004}]

["joey", {:price=>40.27, :numreviews=>814, :avgStarsRank=>44.0, :reviewsrank=>28, :powerrank=>80.054}]

["board", {:price=>14.96, :numreviews=>3, :avgStarsRank=>40.0, :reviewsrank=>0, :powerrank=>47}]

["john", {:price=>40.27, :numreviews=>814, :avgStarsRank=>44.0, :reviewsrank=>28, :powerrank=>16}]

為此，我只想返回一個帶有[“ joey”，“ green”，“ board”]的數組。 關於如何解決這個問題有什么建議嗎？

編輯：這是原始哈希形式的示例：

powerrankings =
    {
        "green"=>{:price=>24.88, :numreviews=>822, :avgStarsRank=>41.0, :reviewsrank=>28, :powerrank=>73.976}, 
        "steve"=>{:price=>14.96, :numreviews=>3, :avgStarsRank=>40.0, :reviewsrank=>0, :powerrank=>42.992000000000004}, 
        "joey"=>{:price=>40.27, :numreviews=>814, :avgStarsRank=>44.0, :reviewsrank=>28, :powerrank=>80.054}}
        "board"=>{:price=>14.96, :numreviews=>3, :avgStarsRank=>40.0, :reviewsrank=>0, :powerrank=>47}, 
        "john"=>{:price=>40.27, :numreviews=>814, :avgStarsRank=>44.0, :reviewsrank=>28, :powerrank=>16}
    }

Answer 1

假設powerrankings不是您顯示的那樣，而是

powerrankings = {
  "green" => {:price=>24.88, :numreviews=>822, :avgStarsRank=>41.0, :reviewsrank=>28, :powerrank=>73.976}, 
  "steve" => {:price=>14.96, :numreviews=>3, :avgStarsRank=>40.0, :reviewsrank=>0, :powerrank=>42.992000000000004}, 
  "joey" => {:price=>40.27, :numreviews=>814, :avgStarsRank=>44.0, :reviewsrank=>28, :powerrank=>80.054},
  "board" => {:price=>14.96, :numreviews=>3, :avgStarsRank=>40.0, :reviewsrank=>0, :powerrank=>47}, 
  "john" => {:price=>40.27, :numreviews=>814, :avgStarsRank=>44.0, :reviewsrank=>28, :powerrank=>16}
}

然后，

powerrankings.sort_by{|_, h| h[:powerrank]}.reverse.first(3).map(&:first)
# => ["joey", "green", "board"]