Python 3.3：拆分字符串並創建所有組合

Question

我使用的是Python 3.3。 我有這個字符串：

"Att education is secondary,primary,unknown"

現在我需要拆分最后三個單詞（可能有更多或只有一個）並創建所有可能的組合並將其保存到列表中。 像這兒：

"Att education is secondary"
"Att education is primary"
"Att education is unknown"

最簡單的方法是什么？

Answer 1

data = "Att education is secondary,primary,unknown"
first, _, last = data.rpartition(" ")
for item in last.split(","):
    print("{} {}".format(first, item))

產量

Att education is secondary
Att education is primary
Att education is unknown

如果你想要列表中的字符串，那么在列表推導中使用相同的，就像這樣

["{} {}".format(first, item) for item in last.split(",")]

注意：如果逗號分隔值中間或值本身中有空格，則可能無效。

Answer 2

a = "Att education is secondary,primary,unknown"
last = a.rsplit(maxsplit=1)[-1]
chopped = a[:-len(last)]

for x in last.split(','):
    print('{}{}'.format(chopped, x))

如果你可以保證你的單詞用單個空格分隔，那么它也會起作用（更優雅）：

chopped, last = "Att education is secondary,primary,unknown".rsplit(maxsplit=1)
for x in last.split(','):
    print('{} {}'.format(chopped, x))

只要最后一個單詞'分隔符不包含空格，就可以正常工作。

輸出：

Att education is secondary
Att education is primary
Att education is unknown

Answer 3

s="Att education is secondary,primary,unknown".split()

w=s[1]
l=s[-1].split(',')

for adj in l:
    print(' '.join([s[0],w,s[2],adj]))