[英]JSON with pretty print
我在java中創建了一個JSONObject,並嘗試使用gson中的漂亮的print函數使對象在網站上更具可讀性,但它仍然顯示為;
{"Back Door":"Unlocked","Window 2":"Unlocked","Window 3":"Unlocked","Window 1":"Unlocked","Front Door":"Unlocked","System":"Disarmed","Lights":"On"}
這是我到目前為止使用gson-2.2.4-javadoc.jar,gson.2.2.4-sources.jar和gson.2.2.4 jar文件的代碼;
import com.google.gson.Gson;
import com.google.gson.GsonBuilder;
@Get("json")
public String handleGet() {
try {
JSONObject system = new JSONObject();
system.put("System", "Disarmed");
system.put("Front Door", "Unlocked");
system.put("Back Door", "Unlocked");
system.put("Window 1", "Unlocked");
system.put("Window 2", "Unlocked");
system.put("Window 3", "Unlocked");
system.put("Lights", "On");
Gson gson = new GsonBuilder().setPrettyPrinting().create();
System.out.println( gson.toJson(system) );
JsonRepresentation jsonRep = new JsonRepresentation(system);
return jsonRep.getText();
} catch (JSONException e) {
e.printStackTrace();
} catch (IOException e)
{
e.printStackTrace();
}
return null;
}
編輯
編輯完這樣的代碼之后;
Gson gson = new GsonBuilder().setPrettyPrinting().create();
System.out.println( gson.toJson(system) );
//JsonRepresentation jsonRep = new JsonRepresentation(system);
String pretty = gson.toJson(system);
return pretty;
//return jsonRep.getText();
} catch (JSONException e) {
e.printStackTrace();
//} catch (IOException e)
{
e.printStackTrace();
}
return null;
}
}
現在它顯示為;
{
"map": {
"Back Door": "Unlocked",
"Window 2": "Unlocked",
"Window 3": "Unlocked",
"Window 1": "Unlocked",
"Front Door": "Unlocked",
"System": "Disarmed",
"Lights": "On"
}
}
有沒有辦法將'map'改為'system'?
只需返回漂亮的印刷Gson輸出
String pretty = gson.toJson(system);
return pretty;
哪個有價值
{
"Lights": "On",
"Front Door": "Unlocked",
"Window 3": "Unlocked",
"Window 2": "Unlocked",
"System": "Disarmed",
"Back Door": "Unlocked",
"Window 1": "Unlocked"
}
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