[英]php read mongodb.findone() returned json values and create object
我有一個雇員類,我想從mongodb.findone()返回的數組初始化雇員對象。
foreach($res as $key => $value){
echo $value; // here values printed
}
但是我需要做一些類似的事情(如果key ='first_name'然后employee_obj-> set_first_name($ value),如果key ='last_name'然后employee_obj-> set_last_name($ value)...)能幫我嗎?
$employee = new Employee;
foreach($res as $key => $value){
if (property_exists($employee, $key)) {
$employee->$key = $value;
}
}
$employee->$key = $value
為雇員動態分配$key
屬性。 例:
$key = "name";
$employee->$key = "John Doe";
echo $employee->name; // John Doe
如果要使用私有或受保護的屬性執行此操作,則需要在類或實例內進行分配:
class Employee {
// ...
private $name;
// lets you assign properties by passing in an array
public function __construct($arr = array()){
if count($arr) {
foreach($arr as $key => $value){
if (property_exists($this, $key)) {
$this->$key = $value;
}
}
}
}
}
$joe = new Employee(array('name' => 'Joe'));
echo $joe->name // Joe
$e = new Employee;
foreach($res as $k => $v){
if($k == 'first_name'){
$e->set_first_name($v);
}elseif($k == 'last_name'){
$e->set_last_name($v);
}else{
$e->$k = $v;
}
}
確實做到了。
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