將目錄路徑作為用戶輸入的正確方法是什么？

Question

下面是我嘗試用來將目錄路徑作為用戶的“原始輸入”的代碼片段。 從用戶輸入后，我收到以下錯誤：

Traceback (most recent call last):
  File "C:\Users\larece.johnson\Desktop\Python Programs\Hello World 2", line 14, in <module>
    f = open(str,"r+")                                     #I open the text file here which the user gave me
IOError: [Errno 2] No such file or directory: 'C:/Users/larece.johnson/Desktop/Python Programs/BostonLog.log.2014-04-01'

忽略我在下面所做的，是否有一種特殊的方式我應該從用戶那里獲取路徑，以便Python接受它？

例如，我正在尋找的目錄和文件是

C:/Users/larece.johnson/Desktop/Python Programs/BostonLog.log.2014-04-01

import re     #this library is used so that I can use the "search" function
import os     #this is needed for using directory paths and manipulating them 

str =""       #initializing string variable for raw data input

#print os.getcwd()
#f = open("C:/Users/larece.johnson/Desktop/BostonLog.log.2014-04-02.log","r+")

str = raw_input("Enter the name of your text file - please use / backslash when typing in directory path: ");  #User will enter the name of text file for me

f = open(str,"r+")

Answer 1

我想你應該嘗試類似的東西：

import sys
import os

user_input = raw_input("Enter the path of your file: ")

assert os.path.exists(user_input), "I did not find the file at, "+str(user_input)
f = open(user_input,'r+')
print("Hooray we found your file!")
#stuff you do with the file goes here
f.close()

Answer 2

您似乎想要檢查目錄是否存在。

如果是這樣，請參閱os.path.isdir 。

os.path.isdir(path)
    Return True if path is an existing directory.
    This follows symbolic links, so both islink()
    and isdir() can be true for the same path.

你可以這樣做：

s = raw_input();
if os.path.isdir(s):
    f = open(s, "r+")
else:
    print "Directory not exists."

Answer 3

我想通了......我忘了在目錄路徑上的文件名末尾添加文件擴展名; 我沒有注意到我只是通過復制/粘貼我的文件名來切斷它....程序現在正在運行...謝謝大家！