從SQLite數據庫中刪除項目並更新ListView

Question

我試圖通過對話框菜單從列表視圖中刪除一個項目。 選擇一個項目后，我將檢索該項目的名稱，並給出一個刪除該項目名稱的選項。 但是當我嘗試刪除並重新加載listview時（請參見圖片）。 我在SQL語句中收到錯誤。

圖片： http : //i.imgur.com/zkmadGf.png

這是刪除方法：

termList.setOnItemClickListener(new OnItemClickListener() {
    @Override
    public void onItemClick(AdapterView<?> adapter, View view, int position, long id) {
        final String termName = ((TextView) view.findViewById(R.id.tv_termName)).getText().toString();
        builder.show();
        builder.setAdapter(menAdapter, new DialogInterface.OnClickListener() {
            @Override
            public void onClick(DialogInterface dialog, int which) {
                String term = termName;
                switch (which) {
                    case 0:
                        Context c = MainActivity.this;
                        Intent i = new Intent(c, CourseListActivity.class);
                        i.putExtra("termName", term);
                        c.startActivity(i);
                        break;
                    case 1:
                        db.delete("termTable", "name = " + term, null);
                        termListAdapter.notifyDataSetChanged();
                }
            }
        });
    }
});

這是日志文件：

04-08 14:27:00.190: E/AndroidRuntime(26451): FATAL EXCEPTION: main
04-08 14:27:00.190: E/AndroidRuntime(26451): android.database.sqlite.SQLiteException: near "Name": syntax error: , while compiling: DELETE FROM termTable WHERE name = Term Name: hello
04-08 14:27:00.190: E/AndroidRuntime(26451):    at android.database.sqlite.SQLiteCompiledSql.native_compile(Native Method)
04-08 14:27:00.190: E/AndroidRuntime(26451):    at android.database.sqlite.SQLiteCompiledSql.<init>(SQLiteCompiledSql.java:68)
04-08 14:27:00.190: E/AndroidRuntime(26451):    at android.database.sqlite.SQLiteProgram.compileSql(SQLiteProgram.java:143)
04-08 14:27:00.190: E/AndroidRuntime(26451):    at android.database.sqlite.SQLiteProgram.compileAndbindAllArgs(SQLiteProgram.java:361)
04-08 14:27:00.190: E/AndroidRuntime(26451):    at android.database.sqlite.SQLiteStatement.acquireAndLock(SQLiteStatement.java:260)
04-08 14:27:00.190: E/AndroidRuntime(26451):    at android.database.sqlite.SQLiteStatement.executeUpdateDelete(SQLiteStatement.java:84)
04-08 14:27:00.190: E/AndroidRuntime(26451):    at android.database.sqlite.SQLiteDatabase.delete(SQLiteDatabase.java:1759)
04-08 14:27:00.190: E/AndroidRuntime(26451):    at com.dagonar.achievegpa.MainActivity$2$1.onClick(MainActivity.java:89)
04-08 14:27:00.190: E/AndroidRuntime(26451):    at com.android.internal.app.AlertController$AlertParams$3.onItemClick(AlertController.java:938)
04-08 14:27:00.190: E/AndroidRuntime(26451):    at android.widget.AdapterView.performItemClick(AdapterView.java:292)
04-08 14:27:00.190: E/AndroidRuntime(26451):    at android.widget.AbsListView.performItemClick(AbsListView.java:1485)
04-08 14:27:00.190: E/AndroidRuntime(26451):    at android.widget.AbsListView$PerformClick.run(AbsListView.java:2941)
04-08 14:27:00.190: E/AndroidRuntime(26451):    at android.widget.AbsListView$1.run(AbsListView.java:3658)
04-08 14:27:00.190: E/AndroidRuntime(26451):    at android.os.Handler.handleCallback(Handler.java:605)
04-08 14:27:00.190: E/AndroidRuntime(26451):    at android.os.Handler.dispatchMessage(Handler.java:92)
04-08 14:27:00.190: E/AndroidRuntime(26451):    at android.os.Looper.loop(Looper.java:137)
04-08 14:27:00.190: E/AndroidRuntime(26451):    at android.app.ActivityThread.main(ActivityThread.java:4464)

希望您能幫助我找到解決方案。

Answer 1

您的目標可能是執行以下語句：

DELETE FROM termTable WHERE name = 'hello'

代替：

DELETE FROM termTable WHERE name = Term Name: hello

因此正確的代碼將是：

String term = termName.split(":")[1].trim();
switch (which) {
    case 0:
        Context c = MainActivity.this;
        Intent i = new Intent(c, CourseListActivity.class);
        i.putExtra("termName", term);
        c.startActivity(i);
        break;
    case 1:
        db.delete("termTable", "name = '" + term + "'", null);
        termListAdapter.notifyDataSetChanged();
}

並且請把標簽和值分成2個TextViews ，不要將所有內容都放在一個TextView 。

Answer 2

將術語值視為“術語名稱：hello”，您需要的是db.delete（“ termTable”，“ name =” +“'+ term +'”，null）;