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[英]SELECT min max and max min value from a part of a table in MySQL
[英]SELECT MAX and MIN from COUNT - MySQL
我有officecode表的員工,我想只顯示有最大值和最小值的員工officecode,
這是桌子
+----------------+------------+
| employeenumber | officecode |
+----------------+------------+
| 1002 | 1 |
| 1056 | 4 |
| 1076 | 1 |
| 1143 | 7 |
| 1165 | 1 |
| 1166 | 6 |
.... .
.... .
+----------------+------------+
這就是我想要得到的 :
+------------+----------+
| officecode | empCount |
+------------+----------+
| 1| 6|
| 7| 2|
+------------+----------+
這是我的方法:
首先,我對它們進行計數和分組
然后從中選擇MAX並與SELECT MIN聯合
但是 SELECT MIN返回錯誤的officecode
這是我的代碼:
SELECT officecode, MAX(empcount) AS 'empcount'
FROM
(
SELECT officecode, count(*) AS 'empCount'
FROM employees
GROUP BY officecode
)
AS temp
UNION
SELECT officecode, MIN(empcount) AS 'empcount'
FROM
(
SELECT officecode, count(*) AS 'empCount'
FROM employees
GROUP BY officecode
)
AS temp2
AS tmp
必須在那里,除非它將返回錯誤
它返回了:
+------------+----------+
| officecode | empCount |
+------------+----------+
| 1| 6|
| 1| 2|
+------------+----------+
有人知道我錯了嗎? 也許您有另一種方法,因為我的方法看起來很糟糕,
(
SELECT officecode, count(*) AS empCount
FROM employees
GROUP BY officecode
ORDER BY empCount ASC
LIMIT 1
)
UNION ALL
(
SELECT officecode, count(*) AS empCount
FROM employees
GROUP BY officecode
ORDER BY empCount DESC
LIMIT 1
)
簡單嘗試一下
SELECT officecode,MAX(empcount),MIN(empcount) count(*) AS 'empCount' FROM employees GROUP BY officecode
你需要這個:
SELECT *
FROM
((SELECT ACTION, COUNT(ACTION) FROM t1
GROUP BY ACTION
ORDER BY ACTION DESC
LIMIT 1)
UNION
(SELECT ACTION, COUNT(ACTION) FROM t1
GROUP BY ACTION
ORDER BY ACTION ASC
LIMIT 1))t
檢查此sqlfiddle: http ://sqlfiddle.com/#!2/7116b5/1
嘗試這個,
SELECT officecode, MAX( empCount ) AS 'empCount'
FROM
(
SELECT officecode, COUNT( * ) AS 'empCount'
FROM employees
GROUP BY officecode ORDER BY empCount DESC
)
AS temp
UNION
SELECT officecode, MIN( empCount ) AS 'empCount'
FROM
(
SELECT officecode, COUNT( * ) AS 'empCount'
FROM employees
GROUP BY officecode ORDER BY empCount ASC
)
AS temp2
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