[英]Find representative who handles the most customers
我正在嘗試列出處理最多客戶的代表。
SELECT RTRIM(S.REP_FNAME) + ' ' + S.REP_LNAME AS [Representative], COUNT(C.REP_NUM) AS Customer(s) Per Rep]
FROM CUSTOMER C, SALESREP S
WHERE S.REP_NUM = C.REP_NUM
GROUP BY RTRIM(S.REP_FNAME) + ' ' + S.REP_LNAME
我的查詢返回:
每個代表的代表客戶
胡安·佩雷斯3
理查德·赫爾4
瓦萊麗·凱澤4
注意*理查德和瓦萊麗是我想要的。 它應該顯示為兩個記錄
如果您需要更多詳細信息,請告訴我。
SELECT RTRIM(S.REP_FNAME) + ' ' + S.REP_LNAME AS [Representative], COUNT(C.REP_NUM) AS [Customer(s) Per Rep]
FROM CUSTOMER C
JOIN SALESREP S
ON S.REP_NUM = C.REP_NUM
GROUP BY RTRIM(S.REP_FNAME) + ' ' + S.REP_LNAME
HAVING COUNT(*) = (SELECT COUNTS FROM (SELECT TOP(1) REP_NUM, COUNT(REP_NUM) AS COUNTS GROUP BY REP_NUM ORDER BY COUNT(REP_NUM) DESC ))
或者您可以使用您給它的名稱。:
ORDER BY [Customer(s) Per Rep] DESC
或者使用不太復雜的方法:
SELECT TOP(1) RTRIM(S.REP_FNAME) + ' ' + S.REP_LNAME AS [Representative], COUNT(C.REP_NUM) AS [Customer(s) Per Rep]
FROM CUSTOMER C, SALESREP S
WHERE S.REP_NUM = C.REP_NUM
GROUP BY RTRIM(S.REP_FNAME) + ' ' + S.REP_LNAME
ORDER BY [Customer(s) Per Rep] DESC
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.