顯示每個用戶的記錄總數

Question

$u=$_POST['userid'];

$sql=mysqli_query($con,"SELECT COUNT(username) AS total FROM TABLENAME where username=$u");

該查詢僅重新調整username=$u的總記錄

我希望所有用戶記錄總計顯示

我想要喜歡的東西

User           Records
User1            1152
user2            2365
user3            2365 
------            -------
userN           XXX

我正在使用php和mysql。

還請告訴。 我應該回聲什么， $sql或Total ？

謝謝你的幫助

我嘗試了這個：並且在行上收到錯誤：

while($fetch = mysql_fetch_assoc($sql))

這是你們給我的代碼

'; print_r（$ array）; mysqli_close（$ con）; ？>

再次感謝

Answer 1

嘗試使用GROUP BY

$sql = mysqli_query($con,"SELECT username, COUNT(username) AS total 
                          FROM TABLENAME GROUP BY username");

$array = array();
while($fetch = mysqli_fetch_assoc($sql))
{
    $array[$fetch['username']] = $fetch['total'];
}

echo '<pre>'; print_r($array);

$array將為您提供所需的內容。

Answer 2

每個用戶都應該這樣做：

SELECT COUNT(username) AS total FROM TABLENAME GROUP BY username

Answer 3

SELECT COUNT(username) AS total FROM TABLENAME GROUP BY username

如果您還想查看它是哪個用戶，只需將其添加到SELECT中：

SELECT username, COUNT(username) AS total FROM TABLENAME GROUP BY username

^如問題中所述，應該這樣做。

要顯示結果：

$u=$_POST['userid'];

$sql=mysqli_query($con,"SELECT COUNT(username) AS total FROM TABLENAME where username=$u");

while ($user = $sql->fetch_assoc()){
    echo($user["username"] . ": " . $user["total"]);
}