[英]Using Ajax in Yii.?
我正在工作門戶網站上,並有一個供雇主搜索申請的搜索模塊。我想使用ajax在搜索后列出申請,並將結果列出在同一頁面中。我應該如何做??,下面是該模塊的屏幕截圖。嘗試過以下操作。
// Contoller代碼//
public function actionSearch()
{
$model = new SearchEmployee();
/*Getting Data From Search Form For Processing */
if (isset($_POST['SearchEmployee'])) {
$model->attributes = $_POST['SearchEmployee'];
$category = $_POST['SearchEmployee']['category'];
$skills = $_POST['SearchEmployee']['skills'];
$experience = $_POST['SearchEmployee']['experience'];
$ajaxmodel = SearchEmployee::model()->find(array(
'select' => array('*'), "condition" => "category_id=$category AND key_skills like'%$skills%'AND experience=$experience",
));
if($model==null)
{
Yii::app()->user->setFlash('success', "No Results");
$this->renderPartial('search');
}
else
{
$this->renderPartial('search', array('model' => $ajaxmodel));
Yii::app()->end();
}
}
//在視圖中,不發布完整的代碼,而只是顯示ajax結果的代碼,//
<div class="view">
<h1>Results </h1>
<div class="view" id="id">
<h1> Records Display </h1>
<h4>Name: <?php echo $form->labelEx($model,'skills Required'); ?></h4>
<h4>Skills: <?php echo $form->labelEx($model,'Skills Required'); ?></h4>
<h4>Experience: <?php echo $form->labelEx($model,'Skills Required'); ?></h4>
<h5> <?php echo CHtml::submitButton('VIew Details'); ?></h5>
</div>
</div>
這是做的事...
在您看來,只需啟用ajax,例如:
$form = $this->beginWidget('bootstrap.widgets.TbActiveForm', array(
'id' => 'client-document-form',
'method' => 'post',
'action' => $url,
'enableAjaxValidation' => false,
'errorMessageCssClass' => 'required_field_text'
)); ?>
此行enableAjaxValidation => true
需要在操作中也為true添加此行$this->performAjaxValidation($model);
更新:
$form = $this->beginWidget('bootstrap.widgets.TbActiveForm', array(
'id'=>'update-profile-form',
'enableAjaxValidation' => true,
'errorMessageCssClass' => 'required_field_text',
'clientOptions' => array(
'validateOnSubmit' => true,
'validateOnChange' => false,
'hideErrorMessage' => true,
'beforeValidate' => 'js:function(form) {
return validate.beforeValidate("update-profile-form");
}',
'afterValidate' => 'js:function(form, data, hasError) {
validate.afterValidate(data, "update-profile-form");
}'
),
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