C ++從文本文件讀取到數組/字符串

Question

這是我到目前為止的代碼。

我需要做的是從兩個不同的文本文件，矩陣A和矩陣B中讀取。

我可以這樣做但是對於我讀過的每個文本文件矩陣，它只能得到它

1 0 0 

（所以基本上是第一行）實際上是Matrix A的整個文本文件

1 0 0
2 0 0
3 0 0

那么有誰知道我怎么做到這一點？

謝謝！

#include <iostream>  //declaring variables
#include <iomanip>
#include <string>
#include <fstream>

using namespace std;
string code(string& line);
int main()
{
    ofstream outf;
    ifstream myfile;
    string infile;
    string line;
    string outfile;

    cout << "Please enter an input file (A.txt) for Matrix A or (B.txt) for Matrix B" << endl;
    cin >> infile;   //prompts user for input file

    if (infile == "A.txt")
    {      //read whats in it and write to screen
        myfile.open("A.txt");
        cout << endl;
        getline (myfile, line);
        cout << line << endl;

    }
    else
        if (infile == "B.txt")
        {
            myfile.open("B.txt");
            cout << endl;
            getline (myfile, line);
            cout << line << endl;
        }
        else
    { 
        cout << "Unable to open file." << endl;
    }
        //{
            //while("Choose next operation");
        //}
    return 0;
}

Answer 1

好吧， getline明顯得到一條線。

你應該逐行閱讀，直到文件結束，你可以用，例如：

while (getline(myfile, line))
    out << line << endl;

這意味着：雖然有一行從myfile獲取，但將該行寫入輸出流。

Answer 2

你只讀一次，所以這不是一個奇跡。 您需要使用while或for循環來連續閱讀。 你會寫這樣的東西：

while (getline (myfile, line))
    cout << line << endl;

這將是要編寫的整個代碼：

#include <iostream>  //declaring variables
#include <iomanip>
#include <string>
#include <fstream>

using namespace std;
string code(string& line);
int main()
{
    ofstream outf;
    ifstream myfile;
    string infile;
    string line;
    string outfile;

    cout << "Please enter an input file (A.txt) for Matrix A or (B.txt) for Matrix B" << endl;
    cin >> infile;   //prompts user for input file

    if (infile == "A.txt")
    {      //read whats in it and write to screen
        myfile.open("A.txt");
        cout << endl;
        while (getline (myfile, line))
            cout << line << endl;


    }
    else
        if (infile == "B.txt")
        {
            myfile.open("B.txt");
            cout << endl;
            while (getline (myfile, line))
                cout << line << endl;
        }
        else
    { 
        cout << "Unable to open file." << endl;
    }
        //{
            //while("Choose next operation");
        //}
    return 0;
}

Answer 3

使用getline是最簡單的方法：

#include <string>
#include <iostream>
#include <fstream>
using namespace std;

void read_file_line_by_line(){
    ifstream file;
    string line;
    file.open("path_to_file");
    while (getline (file, line))
        cout << line << endl;
}

int main(){
    read_file_line_by_line();
    return 0;
}