使用PHP POST方法發布到同一頁面

Question

嘗試使用以前的線程自己弄清楚這一點，但是其他人的示例並不能幫助我弄清楚我需要什么。 獨立文件本身可以工作，數據可以很好地插入數據庫中……但是我正在嘗試對這些文檔進行一些調整，以使其成為一個多合一的單一PHP文檔。

我認為我只會拋出自己想做的事情以及到目前為止的代碼，也許有人會理解我想要完成的事情並能夠解釋如何做。

我基本上有一個帶有form（form.php）的PHP文檔，該文檔使用POST將表單數據發送到第二個PHP文檔，后者又將表單數據發送到MySQL數據庫。 我希望用戶能夠使用同一文檔發布數據並重置數據字段，以便用戶和提交者通過表單輸入更多信息。 我希望使用戶知道由於字段不完整而導致的錯誤，並且希望使用戶知道成功的條目（我將使用echo函數來完成此操作）。

form.php如下：

<html>
<head>
    <link rel="stylesheet" type="text/css" href="form.css">
    <title>MySQL Database Creation System</title>
    <script src="jquery-1.11.0.min.js"></script>
</head>
<body>
    <div class="wrapper">
        <img src="eris.png" align="middle">
        <form action="insert.php" method="post">
        Firstname: <input type="text" size="16" name="firstname">
        Lastname: <input type="text" size="16" name="lastname">
        Age: <input type="text" size="1" maxlength="3" name="age">
        <input type="submit" class="button">
        </form>
    </div>
</body>

insert.php如下：

<html>
<head>
    <link rel="stylesheet" type="text/css" href="insert.css">
    <title>MySQL Database Creation System</title>
</head>
<body>
    <div class="wrapper">
    <img src='eris.png' align='middle'>
        <?php
        if ( (trim($_POST['firstname']) == "") || (trim($_POST['lastname']) == "") || (trim($_POST['age']) == "") )
        {
            echo "<p>ERROR: All fields must be completed</p>";
            echo "<p><a href='form.php'>Return to Form</a></p>";
        }
        else
        {
            $con=mysqli_connect("localhost","test","test","my_db");
            // Check connection
            if (mysqli_connect_errno())
            {
              echo "<br>Failed to connect to MySQL: " . mysqli_connect_error();
            }

            // escape variables for security
            $firstname = mysqli_real_escape_string($_POST['firstname']);
            $lastname = mysqli_real_escape_string($_POST['lastname']);
            $age = mysqli_real_escape_string($_POST['age']);

            $sql="INSERT INTO Persons (FirstName, LastName, Age) 
            VALUES ('$firstname', '$lastname', '$age')";

            if (!mysqli_query($con,$sql))
            {
              die('<br>Error: ' . mysqli_error($con));
            }

            mysqli_close($con);

            echo "<p>New item added.</p>";
            echo "<p><a href='form.php'>Return to Form</a></p>";
        }
        ?>
    </div>

</body>

在此先感謝您提供的任何幫助。

Answer 1

如下還原您的form.php

我在這里做了什么-

1） <form action="insert.php" method="post">
至
<form action="" method="post">

2）在form.php添加了所有php code

 <?php
    if ( (trim($_POST['firstname']) == "") || (trim($_POST['lastname']) == "") ||     (trim($_POST['age']) == "") )
    {
        echo "<p>ERROR: All fields must be completed</p>";
        echo "<p><a href='form.php'>Return to Form</a></p>";
    }
    else
    {
        $con=mysqli_connect("localhost","test","test","my_db");
        // Check connection
        if (mysqli_connect_errno())
        {
          echo "<br>Failed to connect to MySQL: " . mysqli_connect_error();
        }

        // escape variables for security
        $firstname = mysqli_real_escape_string($_POST['firstname']);
        $lastname = mysqli_real_escape_string($_POST['lastname']);
        $age = mysqli_real_escape_string($_POST['age']);

        $sql="INSERT INTO Persons (FirstName, LastName, Age) 
        VALUES ('$firstname', '$lastname', '$age')";

        if (!mysqli_query($con,$sql))
        {
          die('<br>Error: ' . mysqli_error($con));
        }

        mysqli_close($con);

        echo "<p>New item added.</p>";
        echo "<p><a href='form.php'>Return to Form</a></p>";
    }
?>

<html>
<head>
    <link rel="stylesheet" type="text/css" href="form.css">
    <title>MySQL Database Creation System</title>
    <script src="jquery-1.11.0.min.js"></script>
</head>
<body>
<div class="wrapper">
    <img src="eris.png" align="middle">
    <form action="" method="post">
    Firstname: <input type="text" size="16" name="firstname">
    Lastname: <input type="text" size="16" name="lastname">
    Age: <input type="text" size="1" maxlength="3" name="age">
    <input type="submit" class="button">
    </form>
</div>
</body>

Answer 2

我希望我明白這一點。 在這種情況下，您就在附近。 像這樣合並您的腳本：

<?php
// check if there is a post request ...
// if not - nothing happens
if(!empty($_POST))
{
   if ( (trim($_POST['firstname']) == "") || (trim($_POST['lastname']) == "") || (trim($_POST['age']) == "") )
    {
        echo "<p>ERROR: All fields must be completed</p>";
        echo "<p><a href='form.php'>Return to Form</a></p>";
    }
    else
    {
        // your inser code
        $con=mysqli_connect("localhost","test","test","my_db");
        // Check connection
        if (mysqli_connect_errno())
        {
          echo "<br>Failed to connect to MySQL: " . mysqli_connect_error();
        }

        // escape variables for security
        $firstname = mysqli_real_escape_string($_POST['firstname']);
        $lastname = mysqli_real_escape_string($_POST['lastname']);
        $age = mysqli_real_escape_string($_POST['age']);

        $sql="INSERT INTO Persons (FirstName, LastName, Age) 
        VALUES ('$firstname', '$lastname', '$age')";

        if (!mysqli_query($con,$sql))
        {
          die('<br>Error: ' . mysqli_error($con));
        }

        mysqli_close($con);

        echo "<p>New item added.</p>";
        echo "<p><a href='form.php'>Return to Form</a></p>";
    }
}
?>

<html>
<head>
    <link rel="stylesheet" type="text/css" href="form.css">
    <title>MySQL Database Creation System</title>
    <script src="jquery-1.11.0.min.js"></script>
</head>
<body>
    <div class="wrapper">
        <img src="eris.png" align="middle">
        <!-- change insert.php to form.php -->
        <form action="form.php" method="post">
            Firstname: <input type="text" size="16" name="firstname">
            Lastname: <input type="text" size="16" name="lastname">
            Age: <input type="text" size="1" maxlength="3" name="age">
        <input type="submit" class="button">
    </form>
</div>

我希望這接近您的期望。

Answer 3

然后，您的表單頁面應如下所示。

    <html>
    <head>
        <link rel="stylesheet" type="text/css" href="form.css">
        <title>MySQL Database Creation System</title>
        <script src="jquery-1.11.0.min.js"></script>
    </head>
    <body>
        <div class="wrapper">
            <img src="eris.png" align="middle">
            <form action="" method="post">
            Firstname: <input type="text" size="16" name="firstname">
            Lastname: <input type="text" size="16" name="lastname">
            Age: <input type="text" size="1" maxlength="3" name="age">
            <input type="submit" class="button">
            </form>
        </div>
    </body>
    <?php
    if ( (trim($_POST['firstname']) == "") || (trim($_POST['lastname']) == "") || (trim($_POST['age']) == "") )
    {
        echo "<p>ERROR: All fields must be completed</p>";
        echo "<p><a href='form.php'>Return to Form</a></p>";
    }
    else
    {
        $con=mysqli_connect("localhost","test","test","my_db");
        // Check connection
        if (mysqli_connect_errno())
        {
          echo "<br>Failed to connect to MySQL: " . mysqli_connect_error();
        }

        // escape variables for security
        $firstname = mysqli_real_escape_string($_POST['firstname']);
        $lastname = mysqli_real_escape_string($_POST['lastname']);
        $age = mysqli_real_escape_string($_POST['age']);

        $sql="INSERT INTO Persons (FirstName, LastName, Age) 
        VALUES ('$firstname', '$lastname', '$age')";

        if (!mysqli_query($con,$sql))
        {
          die('<br>Error: ' . mysqli_error($con));
        }

        mysqli_close($con);

        echo "<p>New item added.</p>";
        echo "<p><a href='form.php'>Return to Form</a></p>";
    }
    ?>

謝謝

使用PHP POST方法發布到同一頁面

問題描述

3 個解決方案

解決方案1
0 2014-04-20 08:11:17

解決方案2
0 2014-04-20 08:11:38

解決方案3
0 2014-04-20 08:17:07

使用PHP POST方法發布到同一頁面

問題描述

3 個解決方案

解決方案1 0 2014-04-20 08:11:17

解決方案2 0 2014-04-20 08:11:38

解決方案3 0 2014-04-20 08:17:07

解決方案1
0 2014-04-20 08:11:17

解決方案2
0 2014-04-20 08:11:38

解決方案3
0 2014-04-20 08:17:07