[英]MySQL Stored Procedure Dupplication Issue
我希望有人能幫幫忙。 我創建了此存儲過程以從不同的表中提取一些信息,而當我對其進行調整時,我得到了很多重復項,我想知道是否存在一種對它進行排序的方法?
use ICA
if exists(
select *
from INFORMATION_SCHEMA.ROUTINES
where SPECIFIC_SCHEMA = N'ICASchema'
and SPECIFIC_NAME = N'candidateOffer'
)
drop procedure ICASchema.candidateOffer
go
create procedure ICASchema.candidateOffer @candidateID INT
as
begin
select c.CandidateID,c.CandidateName, ca.CourseID, co.CourseName, o.OfferID, ot.OfferTypePoints
from [ICASchema].[tblCandidate] c
join [ICASchema].[tblCandidateOffer] o on c.CandidateID = o.CandidateID
join [ICASchema].[tblOffer] ot on o.offerID = ot.OfferType
join [ICASchema].[tblCandidateApplication] ca on ca.CourseID = ca.CourseID
join [ICASchema].[tblCourse] co on co.CourseName = co.CourseName
where c.CandidateID = @candidateID
--ORDER BY co.CourseName
GROUP BY co.CourseName, c.CandidateID,c.CandidateName, ca.CourseID, o.OfferID, ot.OfferTypePoints
end
go
謝謝
格雷厄姆
嘗試這個:
select * from (select distinct c.CandidateID,c.CandidateName, ca.CourseID, co.CourseName, o.OfferID, ot.OfferTypePoints
from [ICASchema].[tblCandidate] c
join [ICASchema].[tblCandidateOffer] o on c.CandidateID = o.CandidateID
join [ICASchema].[tblOffer] ot on o.offerID = ot.OfferType
join [ICASchema].[tblCandidateApplication] ca on ca.CourseID = ca.CourseID
join [ICASchema].[tblCourse] co on co.CourseName = co.CourseName
where c.CandidateID = @candidateID
GROUP BY co.CourseName, c.CandidateID,c.CandidateName, ca.CourseID, o.OfferID, ot.OfferTypePoints) tablealias order by CourseName
下面的示例用於創建一個簡單的Proc_GetAllUsers存儲過程。 這將解決您的重復問題。
如果存在Proc_GetAllUsers
GO,則刪除程序
創建過程Proc_GetAllUsers()開始
-您的SQL查詢選擇* FROM用戶;
結束
走
這是可行的解決方案。
[代碼]從ICASchema.tblCandidate AS中選擇c.CandidateID,c.CandidateName,ICASchema.tblOffer.OfferTypePoints,ICASchema.tblCourse.CourseName。 ICASchema.tblCandidateOffer.CandidateOfferID = ICASchema.tblOffer.OfferID內部聯接ICASchema.tblCourse ON ICASchema.tblOffer.OfferID = ICASchema.tblCourse.OfferTypeID WHERE(c.CandidateID ='3')[/ code]
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.