Spring WS Endpoint提取SOAP信息

Question

在Spring網站上閱讀了文檔之后，仍然對如何從SOAP請求中提取信息感到困惑。 例如，發送到服務器的SOAP請求類似於：

<soapenv:Envelope xmlns:soapenv="http://www.w3.org/2003/05/soap-envelope" xmlns:user="http://www.mysite.com/user/schemas">
   <soapenv:Header/>
   <soapenv:Body>
      <user:UserRequest>
         <!--You may enter the following 4 items in any order-->
         <user:Key>key</user:Key>
         <user:UserName>username</user:UserName>
         <user:RequesterName>reqname</user:RequesterName>
         <user:RequesterPassword>repw</user:RequesterPassword>
      </user:UserRequest>
   </soapenv:Body>
</soapenv:Envelope>

在服務器端，我創建一個端點，如下所示：

@Endpoint
public class UserEndpoint {

    private static final String NAMESPACE_URI = "http://www.mysite.com/user/schemas";

@PayloadRoot(namespace = NAMESPACE_URI, localPart = "UserRequest")
    public void handleGetUserRequest() {
//Extract here...
    }   
}

我應該如何在此處編寫提取代碼？

Answer 1

我建議看看Spring WS示例中的代碼思想，這取決於您在應用程序中使用的其他內容。 例如：HolidayEndpoint 源代碼 。

Answer 2

@Endpoint("myEndpoint")
public class MyEndpoint {

    /**
     * Spring-WS Endpoint 
     * @param submitSomethingRequest 
     * @param header
     * @return SubmitSomethingResponse
     */
    @PayloadRoot(namespace="http://my.namespace.org/spec/1.0.1", localPart="submitSomethingRequest")
    @ResponsePayload
    public SubmitSomethingResponse submitSomethingRequest(@RequestPayload SubmitSomethingRequest submitSomethingRequest, **SoapHeader header**) {
        LOG.info("Received SOAP HEADER: " + header);
        if(header != null) {
            Iterator<SoapHeaderElement> hdrs = header.examineAllHeaderElements();
            while(hdrs.hasNext()) {
                SoapHeaderElement hdrEle = hdrs.next();
                System.out.prinltn(hdrEle.getName().getPrefix() + ":" + hdrEle.getName().getLocalPart());
                 ... //Do something here to parse DOM and extract headers you care about
            }
        }
...