[英]Inner join in play framework ebean
我有一個查詢,我想在我的產品模型中寫
select * from shop inner join product on product.shops_id=shop.id where product.name=keyword
Shop.java
public class Shop extends Model {
@Id
@SequenceGenerator(name="shop_gen", sequenceName="shop_id_seq", allocationSize=1)
@GeneratedValue(strategy=GenerationType.SEQUENCE, generator="shop_gen")
@Column(name="id")
public Long id;
@Required
public String name;
@Required
public String addressLine1;
public String addressLine2;
public String addressLine3;
@Required
public String city;
@Required
public String town;
@Required
public String phoneNumber;
@OneToMany(mappedBy = "shops",cascade = CascadeType.REMOVE)
public List<Product> products=new ArrayList<>();
@Required
@OneToOne
public String category;
@Lob
@Column(name = "shop_pic")
public byte[] shop_pic;
@ManyToOne
@Required
public User owner;
}
Product.java
public class Product extends Model {
@Id
@SequenceGenerator(name="product_gen", sequenceName="product_id_seq", allocationSize=1)
@GeneratedValue(strategy=GenerationType.SEQUENCE, generator="product_gen")
@Column(name="id")
public Long id;
@Required
public String name;
@Required
public Float price;
@OneToOne
@Required
public String category;
@ManyToOne
public Shop shops;
}
我的主要目的是找到有特定產品的商店列表。
每次關鍵字都會改變。 我提到了類似的問題,但他們理解其中的任何一個。 任何幫助,將不勝感激
在你的模型中有適當的關系,它將是:
Shop.find.where().like("product.name", keyword).findList();
無論如何,我們對你的模型一無所知。
這是您的問題的解決方案:
首先將Finder添加到Product類
public static Finder<Long,Product> find = new Finder<Long,Product>(
Long.class, Product.class
);
將屬性shops
更改為在Product類中shop
。 當有單個對象時給出復數名稱是不合適的。
然后檢索包含給定名稱產品的商店列表添加類似於此的代碼:
List<Product> productList = Product.find.where().like("name", keyword).findList();
List<Shop> shopList = new ArrayList<Shop>();
for(Product product:productList)
shopList.add(product.shop);
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