[英]PHP post to API (trying with cURL)
如果我直接轉到URL中帶有正確參數的URL,則會收到成功響應。
網址看起來像
https://api.theService.com/send?client_id=54&token=7545h5h554&format=json
在PHP中,我嘗試了類似
error_reporting(E_ALL);
ini_set('display_errors', 1);
$client_id = 54;
$token = '7545h5h554';
$ch = curl_init('https://api.theService.com/send?client_id='.$client_id.'&token='.$token.'&format=json');
// Send the request
$response = curl_exec($ch);
// Check for errors
if($response === FALSE){
die(curl_error($ch));
}
// Decode the response
$responseData = json_decode($response, TRUE);
echo "<pre>";
echo print_r($responseData);
echo "</pre>";
但是我沒有收到以上代碼的答復。
嘗試這個:
$client_id = 54;
$token = '7545h5h554';
$url = "https://api.theService.com/send?client_id=$client_id&token=$token&format=json";
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0);
curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1);
curl_setopt($ch, CURLOPT_SSLVERSION, 3);
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 10); //waits 10 seconds for response
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$page = curl_exec($ch) or die(curl_error($ch));
echo $page;
您還應該嘗試檢查curl_error()
的錯誤消息。
http://www.php.net/curl_error
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