在Ruby中將數組打印為表格

Question

我當前的代碼是...

print_line
processes = @client.sys.process.get_processes
blacklist = ["NT AUTHORITY\\SYSTEM", "NT AUTHORITY\\LOCAL SERVICE", "NT AUTHORITY\\NETWORK SERVICE"]
filtered = processes.map!{|i| i.slice!("arch", "session", "path")}.reject {|h| blacklist.include? h['user']}
filtered.each do |r|
puts r.map { |p| p}.join(" ")
end

這是輸出...

pid 0 ppid 0 name [System Process] user 
pid 456 ppid 320 name explorer.exe user CLINE\Administrator
pid 544 ppid 204 name TPAutoConnect.exe user CLINE\Administrator
pid 1096 ppid 456 name vmtoolsd.exe user CLINE\Administrator
pid 180 ppid 456 name rundll32.exe user CLINE\Administrator
pid 1208 ppid 724 name logon.scr user CLINE\Administrator

這是數組...

[*] [{"pid"=>0, "ppid"=>0, "name"=>"[System Process]", "user"=>""}, {"pid"=>456,       "ppid"=>320, "name"=>"explorer.exe", "user"=>"CLINE\\Administrator"}, {"pid"=>544, "ppid"=>204, "name"=>"TPAutoConnect.exe", "user"=>"CLINE\\Administrator"}, {"pid"=>1096, "ppid"=>456, "name"=>"vmtoolsd.exe", "user"=>"CLINE\\Administrator"}, {"pid"=>180, "ppid"=>456, "name"=>"rundll32.exe", "user"=>"CLINE\\Administrator"}, {"pid"=>1208, "ppid"=>724, "name"=>"logon.scr", "user"=>"CLINE\\Administrator"}]

但我希望輸出像表格一樣

pid         ppid        name    user

1           0         x.exe     me

2           1         y.exe    you 

我的代碼中缺少什么？

Answer 1

您可以使用sprintf打印固定寬度的列。 首先獲取每列的最大長度，然后使用sprintf並使用"\\t"所有值：

max_length = filtered.inject({}) {|m,e| e.each{|key,value| m[key] = [key.length, m[key].to_i, value.to_s.length].max}; m}
puts filtered.collect{|e| e.collect{|key,value| sprintf("%#{max_length[key]}s", value)}.join("\t")}

更新：要打印出標題，可以使用以下內容

左對齊：

max_length.collect{|key, value| sprintf("%-#{value}s", key)}.join("\t")

右對齊：

max_length.collect{|key, value| sprintf("%#{value}s", key)}.join("\t")