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PHP img url with preg_match

[英]PHP img url with preg_match

想要只獲得img網址

"//lh5.googleusercontent.com/-0qGW989h9DM/AAAAAAAAAAI/AAAAAAAAG3g/aXkL8mbboKY/photo.jpg"

    <meta itemprop="name" content="Saurabh Sharma">
<meta itemprop="description" content="Works at Google as Product Manager. Lives in San Francisco. Lived in New Delhi - Mumbai - Canonsburg - Pittsburgh - Austin - San Francisco.">
<meta itemprop="image" content="//lh5.googleusercontent.com/-0qGW989h9DM/AAAAAAAAAAI/AAAAAAAAG3g/aXkL8mbboKY/photo.jpg">
<meta itemprop="url" content="https://plus.google.com/+SaurabhSharma">
</head>
<body class="Td lj">
<input type="text" name="hist_state" id="hist_state" style="display:none;">

如何用preg_match做到這一點?

要獲取圖像內容,請使用以下內容

$ data = '<meta itemprop="name" content="Saurabh Sharma"><meta itemprop="description" content="Works at Google as Product Manager. Lives in San Francisco. Lived in New Delhi - Mumbai - Canonsburg - Pittsburgh - Austin - San Francisco."><meta itemprop="image" content="//lh5.googleusercontent.com/-0qGW989h9DM/AAAAAAAAAAI/AAAAAAAAG3g/aXkL8mbboKY/photo.jpg"><meta itemprop="url" content="https://plus.google.com/+SaurabhSharma"></head><body class="Td lj"><input type="text" name="hist_state" id="hist_state" style="display:none;">';

preg_match('/<meta itemprop=\"image\" content=\"(.*?)\">/i', $data, $matches);

$ matches將返回一個數組

Array
(
    [0] => 
    [1] => //lh5.googleusercontent.com/-0qGW989h9DM/AAAAAAAAAAI/AAAAAAAAG3g/aXkL8mbboKY/photo.jpg
)

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