尺寸可變的二維陣列
[英]2D Array with variable size
問題描述
我想要完成的是
String[][] array = new String[sizeX][sizeY]
SizeX基於根JSON數組的長度，sizeY基於根JSON數組內部的數組的長度。
考慮一下，我可以使用單個數組數組，但是我不確定如何引用內部數組以從中獲取信息。 例如：
String[] array = new String[sizeX];
array[i] = new String[sizeY]; // initialized to variable size of JSON
從這里開始，我將如何引用內部數組中的內部數組中的對象？
JSON
{"23591778": {
"pages": [
{
"masteries": [
{
"id": 4211,
"rank": 2
},
{
"id": 4214,
"rank": 2
},
{
"id": 4134,
"rank": 3
},
{
"id": 4124,
"rank": 1
},
{
"id": 4114,
"rank": 1
},
{
"id": 4222,
"rank": 3
},
{
"id": 4112,
"rank": 4
},
{
"id": 4221,
"rank": 1
},
{
"id": 4144,
"rank": 1
},
{
"id": 4122,
"rank": 3
},
{
"id": 4152,
"rank": 3
},
{
"id": 4141,
"rank": 1
},
{
"id": 4111,
"rank": 1
},
{
"id": 4132,
"rank": 1
},
{
"id": 4232,
"rank": 1
},
{
"id": 4162,
"rank": 1
},
{
"id": 4131,
"rank": 1
}
],
"id": 34787712,
"name": "Blind",
"current": false
},
{
"masteries": [
{
"id": 4212,
"rank": 2
},
{
"id": 4233,
"rank": 3
},
{
"id": 4242,
"rank": 1
},
{
"id": 4214,
"rank": 2
},
{
"id": 4114,
"rank": 1
},
{
"id": 4251,
"rank": 1
},
{
"id": 4112,
"rank": 4
},
{
"id": 4222,
"rank": 3
},
{
"id": 4122,
"rank": 3
},
{
"id": 4262,
"rank": 1
},
{
"id": 4224,
"rank": 1
},
{
"id": 4252,
"rank": 3
},
{
"id": 4132,
"rank": 1
},
{
"id": 4241,
"rank": 3
},
{
"id": 4232,
"rank": 1
}
],
"id": 34787713,
"name": "AD/Tank Jungle",
"current": false
},
{
"masteries": [
{
"id": 4242,
"rank": 1
},
{
"id": 4233,
"rank": 3
},
{
"id": 4243,
"rank": 1
},
{
"id": 4211,
"rank": 2
},
{
"id": 4214,
"rank": 2
},
{
"id": 4213,
"rank": 2
},
{
"id": 4114,
"rank": 1
},
{
"id": 4252,
"rank": 2
},
{
"id": 4222,
"rank": 3
},
{
"id": 4113,
"rank": 4
},
{
"id": 4221,
"rank": 1
},
{
"id": 4123,
"rank": 3
},
{
"id": 4262,
"rank": 1
},
{
"id": 4224,
"rank": 1
},
{
"id": 4133,
"rank": 1
},
{
"id": 4234,
"rank": 1
},
{
"id": 4232,
"rank": 1
}
],
"id": 34787714,
"name": "Mumu",
"current": true
},
{
"masteries": [
{
"id": 4211,
"rank": 2
},
{
"id": 4121,
"rank": 1
},
{
"id": 4214,
"rank": 2
},
{
"id": 4134,
"rank": 3
},
{
"id": 4114,
"rank": 1
},
{
"id": 4222,
"rank": 3
},
{
"id": 4112,
"rank": 4
},
{
"id": 4144,
"rank": 1
},
{
"id": 4221,
"rank": 1
},
{
"id": 4152,
"rank": 3
},
{
"id": 4122,
"rank": 3
},
{
"id": 4141,
"rank": 1
},
{
"id": 4111,
"rank": 1
},
{
"id": 4132,
"rank": 1
},
{
"id": 4232,
"rank": 1
},
{
"id": 4162,
"rank": 1
},
{
"id": 4131,
"rank": 1
}
],
"id": 34787715,
"name": "vi/j4/wuk/xin/noc",
"current": false
},
{
"masteries": [
{
"id": 4212,
"rank": 2
},
{
"id": 4353,
"rank": 3
},
{
"id": 4211,
"rank": 2
},
{
"id": 4311,
"rank": 1
},
{
"id": 4362,
"rank": 1
},
{
"id": 4322,
"rank": 3
},
{
"id": 4334,
"rank": 1
},
{
"id": 4332,
"rank": 1
},
{
"id": 4352,
"rank": 1
},
{
"id": 4222,
"rank": 3
},
{
"id": 4314,
"rank": 1
},
{
"id": 4221,
"rank": 1
},
{
"id": 4331,
"rank": 3
},
{
"id": 4324,
"rank": 1
},
{
"id": 4313,
"rank": 3
},
{
"id": 4232,
"rank": 1
},
{
"id": 4342,
"rank": 1
},
{
"id": 4341,
"rank": 1
}
],
"id": 34787716,
"name": "Support",
"current": false
},
{
"masteries": [
{
"id": 4211,
"rank": 2
},
{
"id": 4214,
"rank": 2
},
{
"id": 4124,
"rank": 1
},
{
"id": 4114,
"rank": 1
},
{
"id": 4112,
"rank": 4
},
{
"id": 4222,
"rank": 3
},
{
"id": 4113,
"rank": 4
},
{
"id": 4122,
"rank": 3
},
{
"id": 4152,
"rank": 3
},
{
"id": 4224,
"rank": 1
},
{
"id": 4132,
"rank": 1
},
{
"id": 4142,
"rank": 3
},
{
"id": 4232,
"rank": 1
},
{
"id": 4162,
"rank": 1
}
],
"id": 34787717,
"name": "AD Jungle",
"current": false
},
{
"masteries": [
{
"id": 4212,
"rank": 2
},
{
"id": 4211,
"rank": 2
},
{
"id": 4121,
"rank": 1
},
{
"id": 4134,
"rank": 3
},
{
"id": 4124,
"rank": 1
},
{
"id": 4114,
"rank": 1
},
{
"id": 4222,
"rank": 3
},
{
"id": 4112,
"rank": 4
},
{
"id": 4221,
"rank": 1
},
{
"id": 4122,
"rank": 3
},
{
"id": 4152,
"rank": 3
},
{
"id": 4141,
"rank": 1
},
{
"id": 4142,
"rank": 1
},
{
"id": 4132,
"rank": 1
},
{
"id": 4232,
"rank": 1
},
{
"id": 4162,
"rank": 1
},
{
"id": 4131,
"rank": 1
}
],
"id": 34787718,
"name": "ADC",
"current": false
},
],
"summonerId": 23591778
}}
2 個解決方案
解決方案1
1 已采納 2014-05-05 15:42:31
更新：由於您更新了更多信息，所以這是我的新答案。
您沒有JSON數組的JSON數組，但是有JSON對象的數組。 這些對象又具有一個屬性，即地圖（我相信），但這並不重要。 您正在嘗試使用2D數組而非對象的1D數組。
創建一個代表您的對象的類：
public class MasteryPage {
private long id;
private String name;
private boolean current;
private Map<Long,Integer> masteries = new HashMap<>();
public MasteryPage(long id, String name, boolean current) {
this.id = id;
this.name = name;
this.current = current;
}
public void addMastery(long id, int rank) {
masteries.put(id, rank);
}
// add getters/setters...
}
然后使用您的類創建數組：
JSONArray jArray = json.getJSONArray("pages");
MasteryPage[] arr = new MasteryPage[jArray.length()];
for (int i = 0; i < jArray.length(); i++) {
JSONObject jsonMasteryPage = jArray.getJSONObject(i);
long id = jsonMasteryPage.getLong("id");
String name = jsonMasteryPage.getString("name");
boolean current = jsonMasteryPage.getBoolean("current");
MasteryPage page = new MasteryPage(id, name, current);
JSONArray jsonMasteries = jsonMasteryPage.getJSONArray("masteries");
for (int j = 0; j < jsonMasteries.length(); j++) {
JSONObject jsonMastery = jsonMasteries.getJSONObject(i);
page.addMastery(jsonMastery.getLong("id"), jsonMastery.getInt("rank"));
}
arr.add(page);
}
然后，您可以創建每個精通頁面並解析JSON以填充其字段。
解決方案2
0 2014-05-05 14:39:20
像這樣聲明：
String[][] arr = new String[][numRows];
然后通過以下兩種方式向其添加數組：
arr[0] = new String[lengthOfJSONArray];
arr[0] = getStringArray();
創建一個新的2D數組= 2D數組1的大小+ 2d數組2的大小（行和列）
[英]Creating a new 2D array that = size of 2D array 1 + size of 2d array 2 (rows and columns)
編輯2D數組實例變量大小而無需數組列表（圖像處理）
[英]Edit 2D array instance variable size without Array List (image manipulation)
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