[英]How do I handle only the newest message in the erlang queue?
我正在用Erlang編寫一個游戲引擎,其中服務器不斷向客戶端發送新職位。 我只想使用最新消息並丟棄其余消息,有什么辦法可以做到? 我在客戶端使用Jinterface,所以對此的解決方案將是不錯的。
用erlang不可能(直接)做您說的話。 但是您可以使用中間服務器來實現此行為。 該服務器的作用是接收所有消息並保留最新消息的副本,並通過發送此消息來答復客戶端請求。
-module(latest).
-compile([export_all]).
start() ->
P = spawn(fun() -> loop(empty) end),
register(?MODULE,P).
loop(Last) ->
receive
{newpos,X} -> loop(X);
{getpos,Pid} -> Pid ! Last, loop(empty);
stop -> stopped
end.
% interfaces
storepos(X) -> ?MODULE ! {newpos,X}.
getpos() ->
?MODULE ! {getpos,self()},
receive
M -> M
end.
stop() -> ?MODULE ! stop.
% test func
test() ->
start(),
P1 = spawn(fun() -> posloop(0) end),
P2 = spawn(fun() -> clientloop() end),
{P1,P2}.
endtest({P1,P2}) ->
exit(P1,kill),
exit(P2,kill),
stop().
posloop(I) ->
storepos(I),
timer:sleep(random:uniform(50)),
posloop(I+1).
clientloop() ->
io:format("position at ~p is ~p~n",[erlang:now(),getpos()]),
timer:sleep(random:uniform(200)),
clientloop().
測試結果:
1> A = latest:test().
position at {1399,377773,874000} is 0
{<0.64.0>,<0.65.0>}
position at {1399,377773,967000} is 2
position at {1399,377774,124000} is 6
position at {1399,377774,327000} is 12
position at {1399,377774,436000} is 17
position at {1399,377774,514000} is 19
position at {1399,377774,639000} is 24
position at {1399,377774,827000} is 30
position at {1399,377774,967000} is 34
position at {1399,377775,77000} is 38
position at {1399,377775,202000} is 42
position at {1399,377775,233000} is 43
position at {1399,377775,280000} is 44
position at {1399,377775,436000} is 47
position at {1399,377775,483000} is 48
position at {1399,377775,608000} is 52
position at {1399,377775,655000} is 54
position at {1399,377775,749000} is 57
position at {1399,377775,842000} is 60
position at {1399,377775,858000} is empty
position at {1399,377775,983000} is 63
position at {1399,377776,92000} is 66
position at {1399,377776,186000} is 69
2> latest:endtest(A).
stop
3>
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