[英]tastypie - related resources returning null
我的表中沒有幾個外鍵,我正在嘗試獲取嵌套的資源,但是資源返回空值,即在進行以下調用時
http://localhost:8080/api/v1/testuns/?format=json
我回來
{
meta: {
limit: 20,
next: null,
offset: 0,
previous: null,
total_count: 1
},
objects: [
{
phone: {
devices: null,
modelnumber: null,
phone_id: "2",
resource_uri: "/api/v1/phone/2/"
},
resource_uri: "/api/v1/testuns/0/",
result: "PASS",
score: 90,
test_run_id: "0"
}
]
}
如您所見,我的設備和型號沒有嵌套資源
我的api.py就是這樣
class DevicesResource(ModelResource):
class Meta:
queryset = Devices.objects.all()
authorization = Authorization()
resource_name = 'devices'
class ModelnumberResource(ModelResource):
class Meta:
queryset = Modelnumber.objects.all()
authorization = Authorization()
resource_name = 'modelnumber'
class PhoneResource(ModelResource):
devices = fields.ForeignKey(DevicesResource, 'devices', full=True, null=True)
modelnumber = fields.ForeignKey(ModelnumberResource, 'modelnumber', full=True, null=True)
class Meta:
queryset = Phone.objects.all()
authorization = Authorization()
resource_name = 'phone'
class TestunsResource(ModelResource):
phone = fields.ForeignKey(PhoneResource, 'phone', full=True, null=True)
class Meta:
queryset = Testuns.objects.all()
authorization = Authorization()
resource_name = 'testuns'
而我的models.py是
class Devices(models.Model):
device_id = models.AutoField(primary_key=True)
device_name = models.CharField(max_length=135, unique=True, blank=True)
class Meta:
db_table = u'devices'
class Modelnumber(models.Model):
model_number_id = models.AutoField(primary_key=True)
model_name = models.CharField(max_length=135, unique=True, blank=True)
class Meta:
db_table = u'modelnumber'
class Phone(models.Model):
phone_id = models.AutoField(primary_key=True)
model_number = models.ForeignKey(Modelnumber)
device = models.ForeignKey(Devices)
class Meta:
db_table = u'phone'
class Testuns(models.Model):
test_run_id = models.AutoField(primary_key=True)
score = models.IntegerField()
phone = models.ForeignKey(Phone)
result = models.CharField(max_length=135)
為什么我的某些嵌套資源返回null?
更新:添加mysql查詢
mysql> select * from testuns;
+-------------+-------+----------+--------+
| test_run_id | score | phone_id | result |
+-------------+-------+----------+--------+
| 0 | 90 | 2 | PASS |
+-------------+-------+----------+--------+
1 row in set (0.00 sec)
mysql> select * from phone;
+----------+-----------------+-----------+
| phone_id | model_number_id | device_id |
+----------+-----------------+-----------+
| 2 | 1 | 1 |
+----------+-----------------+-----------+
1 row in set (0.00 sec)
mysql>
偶然地,您的評論向我指出了該解決方案:
class PhoneResource(ModelResource):
device = fields.ForeignKey(DevicesResource, 'device', full=True, null=True)
model_number = fields.ForeignKey(ModelnumberResource, 'model_number', full=True, null=True)
class Meta:
queryset = Phone.objects.all()
authorization = Authorization()
resource_name = 'phone'
完全按照模型中的名稱命名資源字段。
我在自己的項目中對其進行了測試,當資源中的字段名稱與模型中的字段名稱不同時,它將返回null
。
由於null=True
和blank=True
存在,因此該問題具有誤導性。 這使其正常工作,但不符合您的計划。 我在文檔中找不到合適的答案,但在文檔字符串中找到了一些東西:
The ``attribute`` argument should specify what field/callable points to the related data on the instance object. Required.
文檔字符串
編輯:
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.