[英]MySQL - Join & Count rows from another table
我有 3 個表,例如:
parent(id, name)
children(id, data, parent_id, timestamp)
table_votes(id, user_id, child_id)
我想從children
表中獲取具有特定parent_id
所有行,還顯示table_votes
中每個行的出現次數。
我嘗試了以下類似的方法,但似乎不起作用,我想我錯過了在table_votes
沒有條目的所有children
行
SELECT
`children`.`id`,
`children`.`data`,
`children`.`parent_id`,
`children`.`timestamp`,
COUNT(`v`.`children_id`)
FROM `children` LEFT JOIN `table_votes` `v` ON `children`.`id` = `v`.`child_id`
WHERE `children`.`parent_id` = 20 ORDER BY `timestamp` ASC
任何提示我做錯了什么?
先感謝您
有幾種可能的選擇,其中之一:
SELECT * ,
(SELECT count(*)
FROM `table_votes`
WHERE `children`.`id` = `table_votes`.`child_id`) AS `Count`
FROM `children`
WHERE `parent_id` = 20
您也可以使用您的查詢,但必須添加GROUP BY
:
SELECT
`children`.`id`,
`children`.`data`,
`children`.`parent_id`,
`children`.`timestamp`,
COUNT(`v`.`children_id`)
FROM `children` LEFT JOIN `table_votes` `v` ON `children`.`id` = `v`.`child_id`
WHERE `children`.`parent_id` = 20
GROUP BY `children`.`id`, `children`.`data`, `children`.`parent_id`, `children`.`timestamp`,
ORDER BY `timestamp` ASC
1) 帶有子選擇的解決方案:
SELECT
children.id,
children.data,
children.parent_id,
children.timestamp,
(select count(*) from table_votes children.id = table_votes.child_id) as cntVotes
FROM
children
WHERE
children.parent_id = 20
ORDER BY
children.timestamp ASC
2)通過分組解決方案:
SELECT
children.id,
children.data,
children.parent_id,
children.timestamp,
count(table_votes.id) as cntVotes
FROM
children
LEFT JOIN
table_votes ON children.id = v.child_id
WHERE
children.parent_id = 20
GROUP BY
children.id,
children.data,
children.parent_id,
children.timestamp
ORDER BY
children.timestamp ASC
我不確定我是否正確理解了您的問題,但對我而言,您似乎想計算 table_votes 中的兒童數量而不是兒童。 嘗試以下操作:
select id, data, parent_id, timestamp, child_id
from table_votes join children on children_id.id = table_vote.child_id
where child_id = (select count(child_id) from table_vote)
and parent_id = '20'
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