使用PHP從兩個mysql表中選擇數據

Question

我有這個SQL查詢：

SELECT 
  *,
  COUNT(*) as count
from tickets
where
  status = :status 
  and DATE(closed_timestamp) = '".date("Y-m-d")."' 
group by assigned_to 
order by count(*) DESC
LIMIT 3

但我想從tickets表中刪除closed_timestamp列，並基於ticket_updates表中的datetime列運行查詢

ticketnumber在tickets表等於ticketnumber在（多行） ticket_updates表

因此，它應在沒有closed_timestamp列的情況下運行上述查詢，並基於ticket_updates表中的最新datetime值

例

在票證表中有2行，其中票ticketnumber = 1234和5678

在ticket_updates表中有3行。.兩行的ticketnumber = 1234 ，另一行的ticketnumber = 5678

我想顯示票證中status = 'Completed'且上次更新（ ticket_updates表）等於當前日期的所有行（2014-05-19）

Answer 1

使用如下所示的join查詢，

SELECT 
  t.*,
  COUNT(t.*) as count
from tickets as t
LEFT JOIN ticket_updates as tu
ON tu.ticketnumber = t.ticketnumber
where
  t.status = :status 
group by t.assigned_to 
order by count(t.*) DESC
LIMIT 3

Answer 2

嘗試這個：

SELECT *
FROM tickets t
JOIN (
  SELECT ticketnumber
  FROM ticket_updates
  WHERE DATE(datetime) = CURDATE()
) u
ON t.ticketnumber = u.ticketnumber
WHERE status = 'Completed'