[英]Iterate an array of hashes and output each iteration in a row
我有一個哈希數組,例如:
[{:number=>2131, :owner=>"Mark"},
{:number=>223, :owner=>"Mark"},
{:number=>546, :owner=>"Mark"},
{:number=>765454, :owner=>"Tom"},
{:number=>845378, :owner=>"Jack"},
{:number=>75, :owner=>"Jack"},
{:number=>2342, :owner=>"Jack"}]
如何輸出按行排序的所有者的數字值以獲取此信息:
# ["Jack", "Mark", "Tom"]
75 223 765454
2342 546 -
845378 2131 -
具有排序數字的每一列都屬於一個所有者,每行包含來自每個所有者的數字。
關於什么
a = [{:number=>2131, :owner=>"Mark"},
{:number=>223, :owner=>"Mark"},
{:number=>546, :owner=>"Mark"},
{:number=>765454, :owner=>"Tom"},
{:number=>845378, :owner=>"Jack"},
{:number=>75, :owner=>"Jack"},
{:number=>2342, :owner=>"Jack"}]
a1 = a.group_by { |h| h[:owner] }
#=> {"Mark"=>[{:number=>2131, :owner=>"Mark"}, {:number=>223, :owner=>"Mark"}, {:number=>546, :owner=>"Mark"}], "Tom"=>[{:number=>765454, :owner=>"Tom"}], "Jack"=>[{:number=>845378, :owner=>"Jack"}, {:number=>75, :owner=>"Jack"}, {:number=>2342, :owner=>"Jack"}]}
a2 = a1.map { |k, v| [k, v.sort_by { |v| v[:number] } ] }
#=> [["Mark", [{:number=>223, :owner=>"Mark"}, {:number=>546, :owner=>"Mark"}, {:number=>2131, :owner=>"Mark"}]], ["Tom", [{:number=>765454, :owner=>"Tom"}]], ["Jack", [{:number=>75, :owner=>"Jack"}, {:number=>2342, :owner=>"Jack"}, {:number=>845378, :owner=>"Jack"}]]]
a3 = a2.sort_by { |(v0)| v0 }.to_h
#=> {"Jack"=>[{:number=>75, :owner=>"Jack"}, {:number=>2342, :owner=>"Jack"}, {:number=>845378, :owner=>"Jack"}], "Mark"=>[{:number=>223, :owner=>"Mark"}, {:number=>546, :owner=>"Mark"}, {:number=>2131, :owner=>"Mark"}], "Tom"=>[{:number=>765454, :owner=>"Tom"}]}
max_values_size = a3.values.max_by { |v| v.size }.size
#=> 3
a4 = max_values_size.times.map do |i|
a3.keys.map do |k|
a3[k][i] ? a3[k][i][:number] : '-'
end
end
#=> [[75, 223, 765454], [2342, 546, "-"], [845378, 2131, "-"]]
a4.each { |v| puts v.join(' ') }
#=>
75 223 765454
2342 546 -
845378 2131 -
應該很不言自明,問是否不清楚
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