如何獲得一年中每個月的第n個日期

Question

如何獲得每個月的第n個日期（如果為“星期日”），則下一年的下一個即時日期為n + 1。 例如 ：

 Year=2014
 nth value = 2(2nd of each month)

 Date:
 2014-01-02
 2014-02-03 (since 02 is "Sunday" next Immediate date)
 2014-03-03 (since 02 is "Sunday" next Immediate date)
 2014-04-02
 2014-05-02
 2014-06-02
 2014-07-02 
 and so on...

Answer 1

怎么樣， 在這里擺弄

將適用於介於'01'和'28'之間'01'日值，我已經進行了參數檢查並轉換為OP。

DECLARE @Year = Char(4);
DECLARE @Day = VarChar(2);

SET @Year = '2014';
SET @Day = '2';

SELECT
    CASE DATENAME(dw, [Date])
        WHEN 'Sunday' THEN DATEADD(d, 1, [Date])
        ELSE [Date]
    END [Date]
  FROM (
    SELECT
        CAST(@Year + '-' + [M] + '-' + @Day AS DATETIME) [Date]
      FROM (
          SELECT '1' [M] UNION ALL
          SELECT '2' UNION ALL
          SELECT '3' UNION ALL
          SELECT '4' UNION ALL
          SELECT '5' UNION ALL
          SELECT '6' UNION ALL
          SELECT '7' UNION ALL
          SELECT '8' UNION ALL
          SELECT '9' UNION ALL
          SELECT '10' UNION ALL
          SELECT '11' UNION ALL
          SELECT '12') [Months]) [RawDays];

Answer 2

這對我有用...！

    Declare @Tracker int
    set @Tracker = 2

    Declare @FromDate datetime
    Declare @ToDate datetime
    set @FromDate = '2014-01-01'
    set @ToDate = '2014-12-31'

    Declare @TrackerTable Table ( Date Datetime)

    ;with DateDifference As
    (
         SELECT @FromDate DateValue
         UNION ALL
         SELECT  DateValue + 1
         FROM    DateDifference   
         WHERE   DateValue + 1 < @ToDate
    )

    Insert into @TrackerTable
        Select 
            Case 
                when datename(dw,DateValue) = 'Sunday' Then DateValue + 1 
                Else DateValue 
                End as Date
            from DateDifference where Day(DateValue) = @Tracker
            OPTION (MAXRECURSION 0) 

    Select * from @TrackerTable