檢索Facebook個人資料圖片的URL

Question

我有以下代碼具有正確的輸出：

$request = new FacebookRequest( $session, 'GET', '/me?fields=id,first_name,email,gender,birthday,picture.url' );
$response = $request->execute();

OUTPUT：

Facebook\GraphObject Object ( [backingData:protected] => Array ( [id] => 1412361249046879 [first_name] => Do [email] => xxxx@xxxx.com [gender] => male [birthday] => 06/30/1984 [picture] => stdClass Object ( [data] => stdClass Object ( [url] => https://fbcdn-profile-a.akamaihd.net/hprofile-ak-xpa1/t1.0-1/p50x50/10406555_1412406989042185_8978818317524743009_t.jpg ) ) ) )

然后設置變量以供以后在html中調用：

  $uid = $response->getGraphObject()->getProperty('id');
  $name = $response->getGraphObject()->getProperty('first_name');
  $email = $response->getGraphObject()->getProperty('email');
  **$pic = $response->getGraphObject()->getProperty('picture.data.url');**
  $sex = $response->getGraphObject()->getProperty('gender');
  $bday = $response->getGraphObject()->getProperty('birthday');

問題是$ pic變量不起作用。 我不明白如何調用位於GraphObject樹下方的變量（即picture-> data-> url）

Answer 1

$request = new FacebookRequest( $session, 'GET', '/me?fields=id,first_name,email,gender,birthday,picture.url' );
$response = $request->execute();      
$array = $response->getResponse();
$pic = $array->picture->data->url;

這就是解決問題的方法。 我不得不停止使用getGraphObject（）函數，而只是使用標准的getResponse（），以便可以將其更像是常規數組。 希望這可以幫助到別人。

Answer 2

為什么不這樣稱呼它：

$pic = $response->getGraphObject()->getProperty('picture')->data->url;

或將FQL與FB SDK一起使用

$config = array(
  'appId'  => APP_ID,
  'secret' => API_SECRET,
  'cookie' => true,

);
$facebook = new Facebook($config);
$params = array(
    'method' => 'fql.query',
    'query' => "SELECT uid,email, pic, first_name, last_name, birthday, sex FROM user WHERE uid = ".$uid.""
    );

$result = $result = $facebook->api($params);

這是用戶和官方PHP SDK的完整表 。 我希望這有幫助。

警告：但是FQL將從新版本的FB API中刪除。