SQL Server：使用非唯一值的子節點創建XML

Question

我很難弄清楚如何從具有子節點來存儲非唯一值的SQL select中創建XML文件。

我正在使用Microsoft SQL Server 2012

例如

select company, founder
from companies

查詢的結果是：

 microsoft corp       Bill Gates
 microsoft corp       Paul Allen
 apple inc            Steve Jobs
 apple inc            Ronald Wayne
 apple inc            Steve Wozniak

我想生成一個XML

<values>
       <company>microsoft corp</company>
       <founders>
           <founder id="1">Bill Gates</founder>
           <founder id="2">Paul Allen</founder>
       </founders>
</values>
<values>
       <company>apple inc</company>
       <founders>
           <founder id="1">Steve Jobs</founder>
           <founder id="2">Ronald Wayne</founder>
           <founder id="3">Steve Wozniak</founder>
        </founders>
       </company>
</values>

我不確定是否需要節點<founders> ，我認為將創始人直接放在<values>節點下對我來說也很好，因為他們會留在正確的公司中，並獲得ID以包含列表。

我現在使用FOR XML ，然后嘗試了以下不同的選項：

<values>
       <company>apple inc</company>
       <founder>Steve Jobs</founder>
</values>
<values>
       <company>apple inc</company>
       <founder>Ronald Wayne</founder>
</values>
<values>
       <company>apple inc</company>
       <founder>Steve Wozniak</founder>
</values>

這與我當時要實現的目標不兼容。

非常感謝所有將所有創建者置於同一<values>節點下的幫助。

謝謝！

Answer 1

搜索了一下互聯網，找到了解決方案：

DECLARE @table TABLE (company VARCHAR(100), founder VARCHAR(100))

 insert into @table SELECT 'microsoft corp', 'Bill Gates'
 insert into @table SELECT 'microsoft corp', 'Paul Allen'
 insert into @table SELECT 'apple inc', 'Steve Jobs'
 insert into @table SELECT 'apple inc', 'Ronald Wayne'
 insert into @table SELECT 'apple inc', 'Steve Wozniak'


 SELECT company, 
    (
        SELECT ROW_NUMBER()OVER( ORDER BY founder ) as 'founder/@id',
            founder as 'founder'
        FROM @table as F
        WHERE F.company = Comp.company
        FOR XML PATH(''), TYPE
    ) AS founders
 FROM @table as Comp
 GROUP BY company
 FOR XML PATH('VALUES')

結果：

<VALUES>
  <company>apple inc</company>
  <founders>
    <founder id="1">Ronald Wayne</founder>
    <founder id="2">Steve Jobs</founder>
    <founder id="3">Steve Wozniak</founder>
  </founders>
</VALUES>
<VALUES>
  <company>microsoft corp</company>
  <founders>
    <founder id="1">Bill Gates</founder>
    <founder id="2">Paul Allen</founder>
  </founders>
</VALUES>

Answer 2

測試數據

DECLARE @Companies TABLE (company VARCHAR(100), founder VARCHAR(100))
INSERT INTO @Companies VALUES
 ('microsoft corp',       'Bill Gates'),
 ('microsoft corp',       'Paul Allen'),
 ('apple inc',            'Steve Jobs'),
 ('apple inc',            'Ronald Wayne'),
 ('apple inc',            'Steve Wozniak')

詢問

SELECT company
       ,(SELECT ROW_NUMBER() OVER (PARTITION BY Company ORDER BY Founder ASC)  AS [@ID] 
               ,B.founder [text()]
         FROM @companies B
        WHERE B.company = A.company
        FOR XML PATH('Founder'),TYPE) AS Founders
 FROM  @companies A
GROUP BY A.Company       
FOR XML PATH('values'),ROOT('Doc'), ELEMENTS

輸出值

<Doc>
  <values>
    <company>apple inc</company>
    <Founders>
      <Founder ID="1">Ronald Wayne</Founder>
      <Founder ID="2">Steve Jobs</Founder>
      <Founder ID="3">Steve Wozniak</Founder>
    </Founders>
  </values>
  <values>
    <company>microsoft corp</company>
    <Founders>
      <Founder ID="1">Bill Gates</Founder>
      <Founder ID="2">Paul Allen</Founder>
    </Founders>
  </values>
</Doc>